For ksp of silver sulfate (ag2so4) at 1. 2 ✕ 10-5, the solubility of silver sulfate is mathematically given as
x = 5.26*10^{-4}
<h3>What is the
solubility of silver
sulfate in 0.15 M AgNO3?</h3>
Generally, the equation for the Chemical reaction is mathematically given as
Ag2SO4 ⇄ 2Ag+ + SO4 2-
Therefore
Ksp = [Ag+ ]2 *[SO4 2-]
1.2*10-5 = ( 0.15 +2x)2*(x)
x = 5.26*10^{-4}
In conclusion, the solubility of silver sulfate is
x = 5.26*10^{-4}
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Explanation:
The temperature of the molten iron remained constant at 2750°C because of the heat absorbed to effect the phase change and not to change the temperature.
The heat of vaporization is a latent or hidden heat absorbed by substances that causes a phase change from liquid to gas.
- In essence, the heat is used to break intermolecular bonds between the particles of the melted vat.
- If enough heat is no supplied the molten vat will not boil off and become vapor.
- In transitioning from liquid to gas, heat is absorbed by a body to effect the phase change.
- When the body acquires enough heat, the particles are able to break off and boil.
- At the 2750°C mark, this is what is happening.
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Specific heat brainly.com/question/7210400
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I think its C i don't know if i am right
