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timama [110]
3 years ago
15

HCOOH is: formaldehyde formic acid acetone carbon hydroxide

Chemistry
1 answer:
Svet_ta [14]3 years ago
3 0

Answer: formic acid

Explanation:

HCOOH is the structural formula for the compound commonly known as formic acid.

According to the international union of pure applied chemist (IUPAC), it is named methanoic acid, and represent the first member of the alkanoic acids.

Thus, examples of alkanoic acids are

- formic acid (HCOOH)

- Acetic acid (CH3COOH)

- Propanoic acid (CH3CH2COOH) etc

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Suppose the formation of nitrosyl chloride proceeds by the following mechanism: step elementary reaction rate constant 1 NO(g) +
adoni [48]

Answer:

Overall reaction equation;

2NO(g) +Cl2(g) -----> 2NOCl (g)

Explanation:

Given

1) NO(g) + Cl2(g) → NOCl2(g)

2) NOCl2(g) + NO(g) → 2NOCl(g)

Overall reaction equation;

2NO(g) +Cl2(g) -----> 2NOCl (g)

k1= [NOCl2]

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k2 = [NOCl2] [NO]

Equilibrium for the first equation (reaction 1)

K= k1/k-1 = [NOCl2]/[NO] [Cl2]

Therefore

[NOCl2] = k1/k-1 [NO] [Cl2]

Rate= k2× k1/k-1 [NO]^2 [Cl2]

Rate = Koverall [NO]^2 [Cl2]

Where Koverall= k1k2/k-1

3 0
3 years ago
If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol
Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity  :

v_{rms}=\sqrt{\frac{3RT}{M}}

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K.E =\frac{1}{2}mv_{rms}^{2}

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

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K.E_{avg}=\frac{3}{2}RT

T=\frac{2(K.E)}{3(R)}

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T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}

T=345.60K

<u>Now , Use Vrms to calculate the velocity of O2</u>

v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}

v_{rms}=\sqrt{\frac{8619.9552}{0.032}}

v_{rms}=\sqrt{26935.001}

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3 years ago
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Answer:

Explanation:With no acceleration the graph would be flat.

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3 years ago
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Answer:

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