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3 years ago

1.4. A copper cylinder is initially at 20.0 °C. At what temperature will its volume be 0.150% larger than it is at 20.0 °C? (5)

Physics

1 answer:

True [87]3 years ago

8 0

Explanation:

Since, ∆ = − 0, we can find what temperature is required to cause the volume to be 0.15% larger than it is at 20℃: = 0 + ∆ = 20℃ + 29.4℃ = 49.4℃. Answer: = 49.4℃.

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3 years ago

If the coefficient of kinetic friction between tires and dry pavement is 0.93. What is the shortest distance in which you can st

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The shortest distance over which a car moving at 33.6 m/s may be stopped by locking the brakes is 61.93 m

The kinetic friction coefficient is 0.93.

using N, where N is the normal reaction = mg, frictional force can be evaluated.

Fr =- 0.93 x 9.8 = -9.114 m/s²

Friction, which takes the form of a decelerating force, helps the car come to a stop.

This frictional force equals the ma force,

where ma = 7.84 m and a = 7.84 m/s2.

However, this acceleration is negative at 7.84 m/s2 since it is decelerating.

So, using the equations of motion,

v² = u² + 2ax

where;

v = final velocity

u = initial velocity

a = acceleration

0 = 33.6² + 2(-9.114)x

0 = 1128.96 - 18.228x

18.228x = 1128.96

x = 1128.96/18.228

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To know more about shortest distance refer to: brainly.com/question/16751593

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2 years ago

In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 71.5 m/s. Th

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Answer:

957.4845 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-71.5^2}{2\times 250}\\\Rightarrow a=-10.2245\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{0-71.5}{-10.2245}\\\Rightarrow t=6.993\ s$

Time taken by the thunderbird to stop is 6.993 seconds

Time the thunderbird was at the pit is 5 seconds

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{71.5^2-0^2}{2\times 350}\\\Rightarrow a=7.3\ m/s^2$

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{71.5-0}{7.3}\\\Rightarrow t=9.79\ s$

Time taken to accelerate back to 71.5 m/s is 9.79 seconds

Total time to this point is 6.993+5+9.79 = 21.783 seconds

The Mercedes Benz is moving at a constant velocity hence it has no acceleration and we use the formula

Distance = Speed × Time

⇒Distance = 71.5 × 21.783 = 1557.4845 m

The thunderbird has covered 250+350 = 600 m

So, the distance between them is 1557.4845-600 = 957.4845 m

7 0

3 years ago

1.4. A copper cylinder is initially at 20.0 °C. At what temperature will its volume be 0.150% larger than it is at 20.0 °C? (5)​

1.4. A copper cylinder is initially at 20.0 °C. At what temperature will its volume be 0.150% larger than it is at 20.0 °C? (5)