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Maksim231197 [3]

3 years ago

14

An airplane flying at 57 m/s releases a crate of supplies that lands 821 m from where it was released. How high was the plane fl

ying?
1020 m
14.4 m
71 m
5910 m

1 answer:

Mashutka [201]3 years ago

5 0

Answer:1020

Explanation:

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A 600‑kg car accelerates at a rate of 3 m/s2. How much net force is acting on the car to cause this acceleration?

finlep [7]

600(kg) x 3(m/s^2) = 1800N (newtons)

4 0

3 years ago

A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance trave

Svetradugi [14.3K]

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{6 - 0}{6}$

$a = \frac{6}{6}$

Acceleration, a = 1m/s²

<u>To find the distance covered in the first phase;</u>

<em>Solving for distance, we would use the second equation of motion;</em>

$S = ut + \frac {1}{2}at^{2}$

<em>Substituting the values into the equation;</em>

$S = 0(6) + \frac {1}{2}*1*(6)^{2}$

$S = 0 + \frac {1}{2}*1*36$

$S = 0.5 *36$

Distance, S1 = 18m

<u>For the second phase, time T2 = 5 secs;</u>

<em>Mathematically, speed is given by the equation;</em>

$Speed = \frac{distance}{time}$

<em>Making distance the subject of formula, we have;</em>

$Distance, S = speed * time$

<em>Substituting into the above equation;</em>

$Distance, S = 6 * 5$

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

<em>Therefore, the total distance traveled by the biker is 48m.</em>

4 0

3 years ago

A car travels from Boston to Hartford in 4 hours. The two cities are 240 kilometers apart. What was the average speed of the car

Marat540 [252]

Speed=60. 240 divided by 4= 60k which is the total speed

3 0

3 years ago

You are in a tall building located near the equator. What happens to your tangential speed due to the earth's rotation as you ri

8_murik_8 [283]

Answer:increases

Explanation:

If we are going upward in an elevator from the ground floor to the top floor then it indicates that your distance from the center of the earth is increasing while the time period remains the same.

If the radial distance is increased then the tangential velocity of the object must be increased because the time period is the same.

This can be best explained by taking an example of a car moving in a circle of radius r. If radial is increased for the same period then the car has to travel at a higher velocity to make in time.

3 0

3 years ago

1. a) What equal amount of positive charge would have to be placed on the Earth and on the Moon to neutralize their gravitationa

Paul [167]

Answer:

A) q = 5.714 × 10^(13) C

B) Because from a above, F_e = F_g and so r² canceled out in the formulas

C) m_t = 5.964 × 10⁴ kg

Explanation:

For the gravitational attraction of the earth and moon to be neutralized, the electrostatic force must be equal to the gravitational force i.e F_e = F_g

Now, F_e = kq²/r² and F_g = GmM/r²

Equating them and making q the subject, we arrive at;

q = √(GmM/k)

Where;

G is gravitational constant = 6.67 × 10^(-11) m³/kg.s²

m is mass of moon = 7.36 × 10^(22) kg

M is mass of earth = 5.98 × 10^(24) kg

k is coulombs constant = 8.99 x 10^(9) N.m²/c²

q = √(6.67 × 10^(-11) × 7.36 × 10^(22) × 5.98 × 10^(24)/8.99 x 10^(9))

q = 5.714 × 10^(13) C

B) We don't need the lunar distance because from a above, F_e = F_g and so r² canceled out in the formulas.

C) The number of protons is given by the formula;

n = q/e

Where, e is charge of the proton = 1.6 × 10^(-19) C

n = (5.714 × 10^(13))/(1.6 × 10^(-19))

n = 3.57125 × 10^(32)

Total mass of these protons is given by the formula;

m_t = nm_p

Where m_p is mass of a single proton = 1.67 × 10^(-27) kg

m_t = 3.57125 × 10^(32) × 1.67 × 10^(-27)

m_t = 5.964 × 10⁴ kg

5 0

3 years ago