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2 years ago

Solve the following using elimination method

Mathematics

1 answer:

alexgriva [62]2 years ago

5 0

Answer:

the answer of a is 8x+10y

do this by DMAS formula

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ASAP!!! ILL GIVE BRAINLIEST

Ostrovityanka [42]

Answer:

The correct options are 2 and 4.

Step-by-step explanation:

From the given box plot it is clear that

$\text{Minimum value}=20$

$Q_1=25$

$Median=40$

$Q_3=50$

$\text{Maximum value}=110$

We know that these number divides the data in four equal parts.

$Q_1=25\%$

$Median=50%$

$Q_3=75\%$

25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.

Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.

It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.

Therefore option 3 is incorrect.

The interquartile range is

$IQR=Q_3-Q_1=50-25=25$

Therefore option 4 is correct.

The range is

Range = Maximum-Minimum

$Range=110-20=90$

Therefore option 5 is incorrect.

4 0

3 years ago

Andrea and sula ran a race on a track that was 100 meters long.When andrea crossed the finish line sula was exactly 5 meters beh

cestrela7 [59]

Andrea will be at 95 meters and Sula would win I think.

7 0

3 years ago

A survey of 240 families showed that.. 91 had a dog 70 had a cat 31 had a dog and a cat 91 had neither a cat nor a dog nor a par

noname [10]

This is a trick question. 7 families had a parakeet.

3 0

3 years ago

rock is thrown upward with a velocity of 27 meters per second from the top of a 23 meter high cliff and it misses the cliff on t

ahrayia [7]

the rock will be at 11 meters from the ground level after 5.92 seconds

Step-by-step explanation:

The motion of the rock is a free-fall motion, since the rock is acted upon the force of gravity only. Therefore, it is a uniformly accelerated motion, so its position at time t is given by the equation:

$y=h+ut+\frac{1}{2}at^2$

where

h = 23 m is the initial height

u = 27 m/s is the initial velocity, upward

$a=g=-9.8 m/s^2$ is the acceleration of gravity, downward

t is the time

We want to find the time t at which the position of the rock is

y = 11 m

Substituting and re-arranging the equation, we find

$11=23+27t-4.9t^2\\4.9t^2-27t-12=0$

This is a second-order equation, which has solutions:

$t=\frac{27\pm \sqrt{(-27)^2-4(4.9)(-12)}}{2(4.9)}=\frac{27\pm \sqrt{964.2}}{9.8}$

$t_1 = -0.41 s$

$t_2=5.92 s$

The first solution is negative so we neglect it: therefore, the rock will be at 11 meters from the ground level after 5.92 seconds.

Learn more about free fall:

brainly.com/question/1748290

brainly.com/question/11042118

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brainly.com/question/2607086

#LearnwithBrainly

8 0

3 years ago

In the diagram below, AABC-ADEC. What is the value of x?

Marina86 [1]

Answer:

Step-by-step explanation:

Number 4

7 0

2 years ago