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2 years ago

10

Ignore friction. A 20. Lb. Object was lifted to a height of 10 feet by a force of 30. Lb. (a) How much work (ft.Lb) is done by t

he force? (b) Find the change in potential energy (ft.Lb) of the object

1 answer:

Anton [14]2 years ago

4 0

A)
W = Fd
W = (30Lb)(10 ft)
W = 300ft.Lb

b)
work-energy theorem: W = ∆E
∆E = 300ft.Lb

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