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2 years ago

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What is the difference between an empirical issue and ethical issue? (sociology question)

1 answer:

zavuch27 [327]2 years ago

3 0

Answer:

When it comes to research questions, sociologists are best equipped to answer empirical questions. —those that can be answered by real experience in the real world—as opposed to ethical questions. —questions about which people have moral opinions and that may not be answerable in reference to the real world.

Explanation:

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A train is travelong at 22 m/s when the condutor gets a radio call about a car stalled on the tracks. He hits the emergancy brak

mylen [45]

Answer:

final velocity = 0

because the train stoped

so,

acceleration = (v - u) ÷ t
acceleration = (0 - 22) ÷ 135
acceleration = -22 ÷ 135

acceleration = -0.162 m/s²

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2 years ago

A speedboat is approaching a dock at 25 m/s (56 mph). When the dock is 150 m away, the driver begins to slow down. a) What accel

trasher [3.6K]

Answer:

a) -2.038 m/s²

b) 40.33 mph

c) 312.5 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2$

Acceleration of the boat is -2.083 m/s² if the boat will stop at 150 m.

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -1\times 150+25^2}\\\Rightarrow v=18.03\ m/s$

Speed of the boat by when it will hit the dock is 18.03 m/s

Converting to mph

$1\ mile=1609.34\ m$

$1\ h=3600\ seconds$

$18.03\times \frac{3600}{1609.34}=40.33\ mph$

Speed of the boat by when it will hit the dock is 40.33 mph

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-25^2}{2\times -1}\\\Rightarrow s=312.5\ m$

The distance at which the boat will have to start decelerating is 312.5 m

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2 years ago

Use the mass and volume data to calculate the density of liquid propane to the nearest hundredth.

Black_prince [1.1K]

Density = mass/volume
= 4300/10000
= 0.43 g/mL.

Therefore density of liquid propane is 0.43 g/mL.

Hope this helps!

5 0

2 years ago

Read 2 more answers

What force is required to accelerate a 1,000 kg car 5 m/s2?

marysya [2.9K]

F = ma
F = (1000 kg)•(5 m/s^2)
F = 5000 N

5 0

2 years ago

what is the voltage in mv across an 5.5 nm thick membrane if the electric field strength across it is 5.75 mv/m? you may assume

inn [45]

Answer:

V = 31.62 m V

Explanation:

Given,

Voltage across thick membrane = ?

Thickness of the membrane, d = 5.5 n m

Electric field = 5.75 M V/m

we know

$E = \dfrac{V}{d}$

V = E d

V = 5.75 x 10⁶ x 5.5 x 10⁻⁹

V = 31.62 x 10⁻³ V

V = 31.62 m V

Hence, The Voltage across the membrane is equal to 31.62 m V.

3 0

3 years ago