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attashe74 [19]
3 years ago
10

What is the difference between an empirical issue and ethical issue? (sociology question)

Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

When it comes to research questions, sociologists are best equipped to answer empirical questions. —those that can be answered by real experience in the real world—as opposed to ethical questions. —questions about which people have moral opinions and that may not be answerable in reference to the real world.

Explanation:

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I believe the answer is 2.0

Explanation:

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An electron, moving toward the west, enters a uniform magnetic field. Because of this field the electron curves upward. The dire
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Answer:

<em>The magnetic field's direction is towards the north</em>

<em></em>

Explanation:

The force on a positive charge in a uniform magnetic field is represented by the right hand rule. To determine the direction of the force, place your right hand with your palm up, and your thumb at 90° to the other fingers. If the fingers represent the magnetic field, and the thumb the direction of the positive charge, then the palm will push up in the direction of the force. But a negative charge like an electron pushes in exactly the opposite direction. So if you follow this rule, you will find that the magnetic field points towards the north.

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Which lab equipment is used as a cover to prevent heated materials from splattering out of the container and as a holding plate
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Watchglass is a lab equipment that is used as a cover to prevent heated materials from splattering out of the container and as a holding plate for hot or flammable materials

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The ATC notices the airplanes NJ446 and DL267 are flying at the same speed on intersecting courses. What is the problem and what
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Read 2 more answers
A crow is flying horizontally with a constant speed of 2.70m/s when it releases a claim from its beak. The clan lands on the roc
jenyasd209 [6]

Given:

Speed = 2.70 m

Time, t = 2.10 seconds

Let's solve for the following:

• (a) The horizontal component of the velocity.

To find the horizontal component, apply the formula:

V_{ox}=V_o\cos \theta

Where:

Vo is the initial speed = 2.70 m

θ = 0 degrees

Hence, we have:

\begin{gathered} V_{ox}=2.70\cos 0 \\  \\ V_{ox}=2.7\text{ m/s} \end{gathered}

The horizontal component of the velocity just before it lands is 2.70 m/s.

• (b) The vertical component of the velocity.

To find the vertical component, apply the formula:

V_{oy}=V_{0y}-gt=\text{V}_{oy}\text{ sin}\Theta-gt

Where:

g is the acceleration due to gravity = 9.8 m/s²

t is the time = 2.10 s

Hence, we have:

\begin{gathered} V_{oy}=V_{oy}\sin \theta-gt \\  \\ V_{oy}=2.70\sin 0-9.8(2.10) \\  \\ V_{oy}=0-20.58 \\  \\ V_{oy}=-20.58\text{ m/s} \end{gathered}

The vertical component of the velocity just before it lands is -20.58 m/s.

(c) Here, the initial speed is equal to the constant horizontal speed.

Therefore, in part (a) the horizontal component will increase in the x-direction if the speed of the crow is increased.

The initial vertical velocity is 0 m/s in both cases.

Therefore, in part (b) the vertical component will remain constant.

ANSWER:

(a) 2.70 m/s

(b) -20.58

(c) In part (a) the horizontal component will increase, while in part (b) the vertical component will remain constant.

6 0
1 year ago
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