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Nana76 [90]
3 years ago
7

What is the net charge on a sphere that has the following? (a) 5.87 106 electrons and 8.11 106 protons C

Physics
2 answers:
hammer [34]3 years ago
6 0

Answer:

3.58*10⁻¹³ C

Explanation:

When we have a net charge on a sphere, this means that there must be a difference in the number of electrons and protons on the sphere, otherwise, the sphere would be electrically neutral.

In this case, we can find this difference as follows:

Np -Ne = 8.11*10⁶ protons - 5.87*10⁶ electrons = 2.24*10⁶ protons.

The total charge carried by all these protons is just the product of the charge of only one proton (which is equal to the elementary charge e) times the number of excess protons, as follows:

Qnet = 2.24*10⁶ protons * 1.6*10⁻19 C/proton = 3.58*10⁻¹³ C

AysviL [449]3 years ago
3 0

Answer:

3.6 * 10^-13 C

Explanation:

The net charge of the sphere will be the sum of the total electron charge and total proton charge. Mathematically,

Q = Qe + Qp

TOTAL ELECTRON CHARGE:

An electron has an electronic charge of -1.6022 * 10^-19C.

Hence, the charge of 5.87 * 10^6 electrons will be:

Qe = - 1.6022 * 10^-19 * 5.87 * 10^6

Qe = - 9.405 * 10^-13 C

TOTAL PROTON CHARGE:

A proton has an electronic charge of 1.6022 * 10^-19. Hence, 8.11 * 10^6 protons will have:

Qp = 1.6022 * 10^-19 * 8.11 * 10^6

Qp = 1.3 * 10^-12 C

=> Q = (-9.405 * 10^-13) + (1.3 * 10^-12)

Q = 3.6 * 10^-13 C

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This flashlight uses three different forms of energy. Which of these shows the energy changes in the correct order?
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The motion of an electron is given by x(t)=pt3+qt2+r, with p = -2.3 m/s^3 ,q = +1.5 m/s^2 , and r = +9.0 m.A) Determine its velo
alexandr402 [8]

Answer:

v(0)=0\\v(1)=-3.9\ m/s\\v(2)=-21.6\ m/s\\v(3)=-53.1\ m/s

Explanation:

<u>Instant Velocity </u>

Given the position as a function of time x(t), the instant velocity is the derivative of the function:

v(t)=x'(t)

We are given the position as

x(t)=-2.3t^3+1.5t^2+9

The derivative of x is

v(t)=x'(t)=-6.9t^2+3.0t

A) Let's compute v(0)

v(0)=-6.9(0)^2+3.0(0)=0

B)  

v(1)=-6.9(1)^2+3.0(1)

v(1)=-3.9\ m/s

C)

v(2)=-6.9(2)^2+3.0(2)

v(2)=-21.6\ m/s

D)

v(3)=-6.9(3)^2+3.0(3)

v(3)=-53.1\ m/s

4 0
3 years ago
Two 5.0-g aluminum foil balls hang from 1.0-m-long threads that are suspended from the same point at the top. The charge on each
Allisa [31]

Answer: F=0.075N

Explanation:

T*cos(θ) = mg=0.005X9.8

T*cos(θ)=0.049N

T = 0.049/cosθ

F = k*q1*q2 / r2

F = 8.9875 * 10^9 * q1*q2 / r^2 q1

F = 8.9875 * 10^9 * (5 x 10^-6)^2 / r^2

F=0.2246875/r^2

r= 2Lsinθ = 2 x 1 x sinθ =2sinθ

Kindly check the attached for further solution

5 0
3 years ago
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