Just because the book is moving doesn't tell you anything about the forces on it, or even whether there ARE any.
Just look at Newton's first law of motion, and this time, let's try and THINK about it too. It says something to the effect that any object continues in constant, uniform MOTION ..... UNLESS acted on by an external force.
Answer:
Speed of another player, v₂ = 1.47 m/s
Explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
![m_1v_1+m_2v_2=(m_1+m_2)V](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3D%28m_1%2Bm_2%29V)
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
![v_2=-\dfrac{m_1v_1}{m_2}](https://tex.z-dn.net/?f=v_2%3D-%5Cdfrac%7Bm_1v_1%7D%7Bm_2%7D)
![v_2=-\dfrac{88\ kg\times 2\ m/s}{120\ kg}](https://tex.z-dn.net/?f=v_2%3D-%5Cdfrac%7B88%5C%20kg%5Ctimes%202%5C%20m%2Fs%7D%7B120%5C%20kg%7D)
![v_2=-1.47\ m/s](https://tex.z-dn.net/?f=v_2%3D-1.47%5C%20m%2Fs)
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.
China because it is cheaper then getting it from Pittsburgh
Answer:
2.96×10⁸ m/s
Explanation:
Speed = distance / time
v = (2 × 3.85×10⁸ m) / (2.60 s)
v = 2.96×10⁸ m/s
Astronomers can measure a star's<span> position once, and then again 6 months later and </span>calculate<span> the apparent change in position. The </span>star's<span> apparent motion is called stellar </span>parallax<span>. The </span>distance<span> d is measured in parsecs and the </span>parallax<span> angle p is measured in arc seconds.</span>