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Monica [59]
3 years ago
8

What is the main difference between the Schrödinger model and the Bohr atomic model?

Physics
1 answer:
netineya [11]3 years ago
4 0

Answer:

Schrödinger believed that electrons could only exist in orbits, but Bohr stated that electrons could be found anywhere in the atom

Explanation: I got it right on test

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Is the Earth getting larger as more sea floor is added? explain
Natasha_Volkova [10]

The seafloor is only expanding in one area, which is the Atlantic Ocean. It's just Earth's seafloor recylcing itself.

4 0
3 years ago
if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum
fgiga [73]

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6 0
3 years ago
1. What are the units of area under the line/curve?<br> 2. Does the area have any meaning?
TiliK225 [7]

The area under the velocity time graph is 125 m and the meaning of the area is displacement.

<h3>What is area under velocity - time graph?</h3>

The area under a velocity time graph represents the displacement of the object.

total area of the graph = A1 + A2

total area of the graph = ¹/₂ (base₁)(height₁) + ¹/₂ (base₂)(height₂)

total area of the graph = ¹/₂(4)(40) + ¹/₂(3)(30)

total area of the graph = 125 m

Thus, the area under the velocity time graph is 125 m and the meaning of the area is displacement.

Learn more about velocity time graph here: brainly.com/question/4710544

#SPJ1

6 0
1 year ago
What scenario would most likely lead to a higher level of physical fitness among people who live in a city?
ExtremeBDS [4]
More people walk to school or work hope this helps
7 0
3 years ago
What is the maximum angular momentum Lmax that an electron with principal quantum number n = 2 can have? Express your answer in
butalik [34]

Answer:

L_{max} = 1.414 ℏ

Given:

Principle quantum number, n = 2

Solution:

To calculate the maximum angular momentum, L_{max}, we have:

L_{max} = \sqrt {l(1 + l)}                              (1)

where,

l = azimuthal quantum number or angular momentum quantum number

Also,

n = 1 + l

2 = 1 + l

l = 1

Now,

Using the value of l = 1 in eqn (1), we get:

L_{max} = \sqrt {1(1 + 1)} = \sqrt 2

L_{max} = 1.414 ℏ

4 0
3 years ago
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