Answer:
The mercury in the barometer will go down as there is less air pressing down on the bulb of the barometer to push mercury up.
Explanation:
The percentage of light gets through three successive polarized filters is 24.9 %
From the question,
Given that,
Angle of transmission axis = 32.8°
The intensity of light emerging from the first polarizer is determined by the equation
I₁ = I₀ / 2
where I₀ ⇒ intensity of unpolarized light
The light emerging from the second polarizer can be mathematically represented by,
I₂ = I₁ x cos²θ
Substituting the values,
I₂ =( I₀/2) x cos²θ
= (I₀/2) x cos² (32.8 )
= (I₀/2) x 0.706
= (0.706 / 2 ) x I₀
The light emerging from the third polarizer is represented as,
I₃ = I₂ x cos²θ
Substituting the values in the above equation,
I₃ = ( 0.706 / 2 ) I₀ x cos² (32.8)
= (0.706 / 2 ) I₀ x 0.706
= 0.249 I₀
The percentage of intensity of light that gwts through with respect to the intensity of unpolarized light is given by the equation,
(I₃ / I₀) x 100
Substituting the values
[(0.249 x I₀) / I₀ ] x 100 = 24.9 %
Hence the percentage of light gets through is 24.9%
To learn more about unpolarized light: brainly.com/question/17164167
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Answer:
CB = 4.45 x 10⁻⁹ F = 4.45 nF
Explanation:
The capacitance of a parallel plate capacitor is given by the following formula:
C = ε₀A/d
where,
C = Capacitance
ε₀ = Permeability of free space
A = Area of plates
d = Distance between plates
FOR CAPACITOR A:
C = CA = 17.8 nF = 17.8 x 10⁻⁹ F
A = A₁
d = d₁
Therefore,
CA = ε₀A₁/d₁ = 17.8 x 10⁻⁹ F ----------------- equation 1
FOR CAPACITOR B:
C = CB = ?
A = A₁/2
d = 2 d₁
Therefore,
CB = ε₀(A₁/2)/2d₁
CB = (1/4)(ε₀A₁/d₁)
using equation 1:
CB = (1/4)(17.8 X 10⁻⁹ F)
<u>CB = 4.45 x 10⁻⁹ F = 4.45 nF</u>
Answer: An oxbow lake forms after there has been deposition of sediment, by the new cutoff channel flowing adjacent to it, at the entrances of the abandoned bend; this seals the bend off from the rest of the river.
