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3 years ago

4 what is the difference between an array's size declarator and a subscript?

1 answer:

Ber [7]3 years ago

7 0

What is the difference between asize declarator and a subscript? The size declarator is ... When writing a function that accepts a two-dimensional array as an argument, which size declarator must you provide in the parameter for thearray? The second size ...

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An escalator is 18.3 m long. If a person stands on the escalator, it takes 47.8 s to ride from the bottom to the top. If a perso

Novay_Z [31]

Answer:

20.243 s

Explanation:

Because the escalator and person moving in the same direction, relative velocity can be calculated by summing the velocity of the escalator and velocity of the person.

The speed of escalator can be calculated as,

$v_{escalator}=\frac{x}{t}=\frac{18.3}{47.8}=0.383\ m/s$

Relative velocity

$v_{relative}=v_{escalator}+v_{person}\\\\v_{relative}=0.383+0.521=0.904\ m/s\\$

Therefore total time required to take the person to get to the top

$t=\frac{x}{v_{relative}}= \frac{18.3}{0.904}=20.243\ s$

8 0

3 years ago

Please help me with the question below the best answer with an explanation will get brainliest

lesya [120]

Answer:

Explanation:

i hope this is correct.

6 0

2 years ago

Describe an original example of energy changing from one form to two other forms

irinina [24]

1). an electric motor running
Electrical energy is changing into kinetic energy and a little bit of heat

2). light a match
The chemical energy stored in the match head changes into light and heat energy.

3). a light bulb
Electrical energy is changed into light and heat energy.

8 0

3 years ago

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to f

amid [387]

You need to first measure the angle of descent, i.e. the angle the hill makes with the ground. Then identify the forces acting on the sled, split them up into horizontal and vertical components, or into components that are parallel and perpendicular to the hill, and use Newton's second law to determine the components of the sled's acceleration vector.

There are at least 2 forces acting on the sled:

• its weight, pointing downward with magnitude W = m g

• the normal force, pointing perpendicular to the hill and away from the ground with mag. N

The question doesn't specify, but there might also be friction to consider, indicated in the attachment by the vector F pointing parallel to the slope of the hill and opposing the direction of the sled's motion with mag. F.

Splitting up the forces into parallel/perpendicular components is less work. By Newton's second law, the net force (denoted with ∑ or "sigma" here) in a particular direction is equal to the mass of the sled times its acceleration in that direction:

∑ (//) = W (//) = m a (//)

∑ (⟂) = W (⟂) + N = m a (⟂)

where, for instance, W (//) denotes the component of the sled's weight in the direction parallel to the hill, while a (⟂) denotes the component of the sled's acceleration perpendicular to the hill. If there is friction, you need to add -F to the first equation.

If the hill makes an angle of θ with flat ground, then W makes the same angle with the hill so that

W (//) = -m g sin(θ)

W (⟂) = -m g cos(θ)

So we have

-m g sin(θ) = m a (//) → a (//) = -g sin(θ)

-m g cos(θ) + N = m a (⟂) → a (⟂) = 0

where the last equality follows from the fact that the normal force exactly opposes the perpendicular component of the weight. This is because the sled is moving along the slope of the hill, and not into the air or into the ground.

Then the acceleration vector is

a = a (//)

with magnitude

||a|| = a = g sin(θ).

6 0

3 years ago

What factors contribute to global winds

serg [7]

Temperature and elevation, if it is cold in Idaho and warm on the eastern end of a mountain side in california (or if warm air is going in that direction) then the cold air, being more dense, will go towards california while the cold air in Idaho will become warm. Same goes for the rest of the world

3 0

3 years ago