A 5.3 kg block initially at rest is pulled to the right along a frictionless, horizontal surface by a constant horizontal force
of magnitude 21 N. Find the block's speed after it has moved through a horizontal distance of 6.4 m.
2 answers:
Answer:
F= MASS *ACCELERATION
12=6*a
a=2 m/sec^2
v^2-u^2=2*a*s
v^2=2*2*3
v=sqrt(12)
v=3.5 m/sec
work done by force= change in kinetic energy
F*S=0.5*M*U^2-0.5*M*V^2
12*3=0 0.5*6*V^2
V=3.46 M/SEC
Explanation:
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I think the answer to that questions is B.
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