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Soloha48 [4]
3 years ago
7

A 5.3 kg block initially at rest is pulled to the right along a frictionless, horizontal surface by a constant horizontal force

of magnitude 21 N. Find the block's speed after it has moved through a horizontal distance of 6.4 m.
Physics
2 answers:
Anni [7]3 years ago
6 0
Whatever the person said
dimulka [17.4K]3 years ago
3 0

Answer:

F= MASS *ACCELERATION

12=6*a

a=2 m/sec^2

v^2-u^2=2*a*s

v^2=2*2*3

v=sqrt(12)

v=3.5 m/sec

work done by force= change in kinetic energy

F*S=0.5*M*U^2-0.5*M*V^2

12*3=0 0.5*6*V^2

V=3.46 M/SEC

Explanation:

#if you need any queshtions answered within secs mins hit me up and I got you!

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You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc
FrozenT [24]

Answer:

The balloon hit the ground with velocity -15.34 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

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We consider that the 12 meters is the maximum height, so the velocity

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To find the velocity when the balloon hits the ground lets use the rule

<em>v² = u² + 2gh</em>, where v is the final velocity, u is the initial velocity, g is

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u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

v² = 0 + 2(9.8)(12)

v² = 235.2

<em>Take square root for both sides</em>

v = ± \sqrt{235.2}

The velocity is downward, then it's a negative value

Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

6 0
3 years ago
Which planet in the list below is larger than Earth? A. Saturn B. Mars C. Mercury D. Venus
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so the correct answer is

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4 0
3 years ago
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