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Soloha48 [4]
3 years ago
7

A 5.3 kg block initially at rest is pulled to the right along a frictionless, horizontal surface by a constant horizontal force

of magnitude 21 N. Find the block's speed after it has moved through a horizontal distance of 6.4 m.
Physics
2 answers:
Anni [7]3 years ago
6 0
Whatever the person said
dimulka [17.4K]3 years ago
3 0

Answer:

F= MASS *ACCELERATION

12=6*a

a=2 m/sec^2

v^2-u^2=2*a*s

v^2=2*2*3

v=sqrt(12)

v=3.5 m/sec

work done by force= change in kinetic energy

F*S=0.5*M*U^2-0.5*M*V^2

12*3=0 0.5*6*V^2

V=3.46 M/SEC

Explanation:

#if you need any queshtions answered within secs mins hit me up and I got you!

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Explanation:

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3 years ago
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What is the acceleration of the the object during the first 4 seconds?
AVprozaik [17]

Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

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3 years ago
sest yourse 1. A pencil lies on the dashboard of a car. a) i) What happens to the pencil when the car suddenly stops? suddenly a
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Answer:

1. the pencil would have the momentum and would keep going until it hits the windshield. 2. when the car suddenly accelerates, the pencil would be inert and it would move toward the back of the car until a constant speed from the car is reached.

8 0
2 years ago
A small fan has blades that have a radius of 0.0600 m. When the fan is turned on, the tips of the blades have a tangential accel
zhuklara [117]

Answer:

α = 395 rad/s²

Explanation:

Main features of uniformly accelerated circular motion

A body performs a uniformly accelerated circular motion   when its trajectory is a circle and its angular acceleration is constant  (α = cte). In it the velocity vector is tangent at each point to the trajectory and, in addition, its magnitude varies uniformly.

There is tangential acceleration (at) and is constant.

at = α*R     Formula (1)

where

α  is the angular acceleration

R is the radius of the circular path

There is normal or centripetal acceleration that determines the change in direction of the velocity vector.

Data

R = 0.0600 m   :blade radius

at = 23.7 m/s² : tangential acceleration of the blades

Angular acceleration of the blades (α)

We replace data in the formula (1)

at = α*R  

23.7 = α*(0.06)

α = (23.7) / (0.06)

α = 395 rad/s²

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