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2 years ago

Which two factors are used to calculate the kinetic energy of an object?

Chemistry

2 answers:

Mashcka [7]2 years ago

6 0

Answer:

it should be velocity and mass

hoa [83]2 years ago

4 0

I believe it is Velocity and mass

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A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C

Mamont248 [21]

Answer:

$T_{eq}=23.85^oC$

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

$\Delta H_{Cu}=-\Delta H_{H_2O}$

Therefore the equilibrium temperature shows up as:

$m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\$

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

$T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC$

Best regards.

6 0

3 years ago

Read 2 more answers

Complete combustion of 8.10 g of a hydrocarbon produced 25.9 g of CO2 and 9.27 g of H2O. What is the empirical formula for the h

balu736 [363]

CxHy + O2 --> x CO2 + y/2 H2O

Find the moles of CO2 : 18.9g / 44 g/mol = .430 mol CO2 = .430 mol of C in compound

Find the moles of H2O: 5.79g / 18 g/mol = .322 mol H2O = .166 mol of H in compound

Find the mass of C and H in the compound:

.430mol x 12 = 5.16 g C

.166mol x 1g = .166g H

When you add these up they indicate a mass of 5.33 g for the compound, not 5.80g as you stated in the problem.

Therefore it is likely that either the mass of the CO2 or the mass of H20 produced is incorrect (most likely a typo).

In any event, to find the formula, you would take the moles of C and H and convert to a whole number ratio (this is usually done by dividing both of them by the smaller value).

8 0

3 years ago

A substance with a high [H ] would likely have which additional characteristics? a high [OHĂ˘â‚¬"" ] and a high pOH a low [OHĂ˘â

viktelen [127]

The negative log function that determines the acidity or alkalinity by hydronium ion concentration is called pH.

The substance having high $\rm [H]$ will have:

Option B. A low $\rm [OH ^{-}]$ and a high $\rm pOH$

This characteristic can be explained as:

The concentrations of $\rm [H^{+}]$ and $\rm [OH ^{-}]$ are inversely dependent on each other so when the concentration of raises then the concentration of $\rm [OH ^{-}]$ drops and vice versa.

The pH of a solution or substance is calculated with the help of:

$\rm pH = \rm - log \rm [H^{+}]$

From the formula, it can be deduced that when the concentration of $\rm [H^{+}]$ is high then the pH has a low value and it means that the solution is acidic.