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Free_Kalibri [48]

3 years ago

15

What is the difference between what happens to the light waves when they reach the "golden" colored mask

2 answers:

Yuri [45]3 years ago

4 0

Answer:

Explanation:

b gvgbhkn

Natasha_Volkova [10]3 years ago

3 0

Answer:

I believe the black mask absorbs all light while the golden absorbs everything but whatever color it is that makes a golden hue.

Explanation:

This is because black is void of all colors. when something has a certain pigment, you immediately know that all colors are absorbed acept for the one you can see because it reflects off of it and the waves hit your eyes just right, making it come off as that color. (I believe)

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State Newtons first law of motion.

Fofino [41]

Answer:

An object at rest will stay at rest and an object in motion will stay in motion unless it is acted upon by an unbalanced/external force.

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A spring-loaded toy gun is used to shoot a ball of mass straight up in the air, as shown in the figure. The spring has spring co

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Answer:

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Explanation:

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6 0

3 years ago

Tom [10]

The answers are A and E!

6 0

3 years ago

An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large o

Alekssandra [29.7K]

Answer:

$0.53m/s^2$

Explanation:

We are given that

Mass of wire=m=3.6 g= $3.6\times 10^{-3} kg$

1 kg=1000 g

Length of wire=l=1.6 m

Mass of object=m'=3 kg

Time,t=60.1 ms= $60.1\times 10^{-3} s$

$1 ms=10^{-3} s$

Speed,v= $\frac{distance}{time}=\frac{1.6}{60.1\times 10^{-3}}=26.62 m/s$

$g=\frac{v^2m}{m'l}$

Using the formula

$g=\frac{(26.62)^2\times 3.6\times 10^{-3}}{3\times 1.6}=0.53m/s^2$

8 0

4 years ago

A system gains 767 kJ of heat, resulting in a change in internal energy of the system equal to +151 kJ. How much work is done?

Crazy boy [7]

Answer:

The work done on the system is -616 kJ

Explanation:

Given;

Quantity of heat absorbed by the system, Q = 767 kJ

change in the internal energy of the system, ΔU = +151 kJ

Apply the first law of thermodynamics;

ΔU = W + Q

Where;

ΔU is the change in internal energy

W is the work done

Q is the heat gained

W = ΔU - Q

W = 151 - 767

W = -616 kJ (The negative sign indicates that the work is done on the system)

Therefore, the work done on the system is -616 kJ

6 0

3 years ago