<span>the electrons change their energy states and photons in visible spectrum (and infrared spectrum) are emitted.More the losses, more would be the light, but at the same time, more would be the heat generated.So
this necessitates that the metal used should have high resistivity (and
hence high losses), good thermmal conductivity and high melting point.
hope it helps
</span>
Gasoline and motor oil are chemically similar. They are both mixtures of nonpolar hydrocarbons containing carbon and hydrogen atoms. However, motor oil is much more viscous Motor Oil
A chef is using honey in a recipe. The honey is too thick to pour out of the jar. How could the chef make the honey easier to pour? heat it
Water’s molar mass is 18.01 g/mol. The molar mass of methanol is 32.01 g/mol. At room temperature, water is 64% more viscous than methanol. Which substance has the stronger intermolecular attraction? water
Solution :
Compound Ksp


FeS 


Ksp of
and both compounds dissociate the same way. Hence
is more soluble than 
is less soluble than 
It is not possible to determine CD -
is more or less soluble than
as though they have a different Ksp values their molecular dissociation is also different and they may have a close solubility values.
can be directly compared with PbS, 



100
1-s s 2s
Ksp = ![[A2+][B-]^2 = s \times (2s)^2 = 4s^3](https://tex.z-dn.net/?f=%5BA2%2B%5D%5BB-%5D%5E2%20%3D%20s%20%5Ctimes%20%282s%29%5E2%20%3D%204s%5E3)
Hence they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
For Silver Chloride


1 0 0
1 - s s s
Ksp ![$=[A^{x+}][B^{x-}]=s \times s = s^2$](https://tex.z-dn.net/?f=%24%3D%5BA%5E%7Bx%2B%7D%5D%5BB%5E%7Bx-%7D%5D%3Ds%20%5Ctimes%20s%20%3D%20s%5E2%24)
Hence, they can be directly compared by Ksp values, smaller the Ksp, smaller the solubility.
A. It is Basic
for example,
NaOH → Na⁺(aq) + OH⁻(aq)
Ba(OH)₂ → Ba²⁺(aq) + 2OH⁻(aq)
Ca(OH)₂ → Ca²⁺(aq) + 2OH⁻(aq)
pH>7
Answer:
ork out which of the displacement (S), initial velocity (U), acceleration (A) and time (T) you have to solve for final velocity (V).
If you have U, A and T, use V = U + AT.
If you have S, U and T, use V = 2(S/T) - U.
If you have S, U and A, use V = SQRT(U2 + 2AS)