The reactant being used up is called limiting reagent as it limits the total amount of product produced.
if 4 units of HCL gives 2 units of Cl therefore
4:2
0.98:x
x=(0.98*2) /4
x=0.49L
Answer:
You will have 19.9L of Cl2
Explanation:
We can solve this question using:
PV = nRT; V = nRT/P
<em>Where V is the volume of the gas</em>
<em>n the moles of Cl2</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is 273.15K assuming STP conditions</em>
<em>P is 1atm at STP</em>
The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:
63g * (1mol / 70.906g) = 0.8885 moles
Replacing:
V = 0.8885mol*0.082atmL/molK*273.15K/1atm
V = You will have 19.9L of Cl2
Answer:
The answer to your question is: CH₄ + 3/2 O₂ ⇒ CO₂ + 2 H₂O
Explanation:
Methane = CH₄
Oxygen = O
Carbon dioxide = CO₂
Water = H₂O
CH₄ + 3/2 O₂ ⇒ CO₂ + 2 H₂O
This is the balanced equation
Answer:
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