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3 years ago

Find an exponential function to model the data.

Mathematics

1 answer:

kicyunya [14]3 years ago

5 0

Answer: C

Step-by-step explanation:

The best approximation is C

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Medal will be awarded:. When constructing an inscribed polygon with a compass and straightedge, how should you start the constru

Ymorist [56]

The draw an inscribed polygon inside the circle, the very thing to do is to draw the circle. Thus, the answer is the fourth choice, "Place a point on your paper and then use a compass to construct a circle". After which, we can locate the vertices of the polygon in the circumference of the circle and connect them to make the polygon.

6 0

3 years ago

C + 6 > 5c - 2<br>solved and proof

Elena L [17]

Hi there!

»»————-　★　————-««

I believe your answer is:

c < 2

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$c+6>5c - 2\\--------------\\\\\rightarrow5c - 2< c + 6 \leftarrow \text{Notice how the sides are switched.}\\\\\rightarrow 5c - c -2 < c - c + 6\\\\\rightarrow 4c -2 < 6\\\\\rightarrow 4c - 2 + 2 < 6 + 2\\\\\rightarrow 4c < 8\\\\\rightarrow \frac{4c$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

4 0

2 years ago

1) Ethan put $700 into a Certificate of Deposit (CD) account that earns 1.8% interest each year. What will the interest of the C

Inga [223]

Answer:

The interest After 6 years is $ 79.03

Step-by-step explanation:

Given as :

The principal amount deposited in account = $ 700

The rate interest earn = 1.8 % per year

The Time period = 6 years

<u>From Compounded Method </u>

Amount = Principal × $(1 +\dfrac{\textrm Rate}{100})^{\textrm Time$

Or, Amount = $ 700 × $(1 +\dfrac{\textrm 1.8}{100})^{\textrm 6$

Or, Amount = $ 700 × $1.018^{6}$

Or, Amount = $ 700 × 1.1129

∴ Amount = $ 779.03

Now , Interest = Amount - Principal

I.e Interest = $ 779.03 - $ 700 = $ 79.03

Hence The interest After 6 years is $ 79.03 , Answer

7 0

3 years ago

Read 2 more answers

Solve the following equation. X cubed minus 6X squared plus 6X equals zero

anyanavicka [17]

We have to solve this equation:

$x^3-6x^2+6x=0$

Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:

$\begin{gathered} x^3-6x^2+6x=0 \\ x(x^2-6x+6)=0 \end{gathered}$

Now we can find the roots of the quadratic polynomial as:

$\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}$

Then, the solutions to the equation are:

x = 0

x = 3 - √3

x = 3 + √3

4 0

1 year ago

A spring exerts a force of 6 N when stretched 3 m beyond its natural length. How much work is required to stretch the spring 2 m

lys-0071 [83]

Answer:

4Joules

Step-by-step explanation:

According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

K is the elastic constant

e is the extension

If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'

can be gotten using k = f/e where

F = 6N, e = 3m

K = 6N/3m

K = 2N/m

Work done on an elastic string is calculated using 1/2ke².

If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;

1/2× 2× (2)²

= 4Joules

3 0

3 years ago