Answer:
Mass = 73.73 g
Explanation:
Given data:
Mass of Mg used = 24.48 g
Mass of HCl used = ?
Mass of hydrogen gas produced = 2.04 g
Mass of Magnesium chloride produced = 96.90 g
Solution:
Chemical equation:
Mg + 2HCl → MgCl₂ + H₂
Number of moles of Mg:
Number of moles = mass/ molar mass
Number of moles = 24.48 g/ 24.305 g/mol
Number of moles = 1.01 mol
Now we will compare the moles of Mg with HCl from balance chemical equation.
Mg : HCl
1 ; 2
1.01 : 2/1× 1.01 = 2.02 mol
Mass of HCl react:
Mass = number of moles × molar mass
Mass = 2.02 × 36.5 g/mol
Mass = 73.73 g
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This reaction obeys the law of conservation of mass.
Explanation:
In the burning reaction, methane (CH₄) react with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O):
CH₄ + 2 O₂ → CO₂ + 2 H₂O
Now we calculate the number of moles of methane and carbon dioxide:
number of moles = mass / molar weight
number of moles of methane = 10 / 16.04 = 0.62 moles
number of moles of carbon dioxide = 27 / 44.01 = 0.61 moles
From the chemical reaction we see that 1 mole of methane produces 1 moles of carbon dioxide so 0.6 moles of methane produces 0.6 mole of carbon dioxide. This reaction obeys the law of conservation of mass because the mass of reactants is equal to the mass of products.
Learn more about:
combustion reaction
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<span>Weight of CaC2 is 1.53 g
Temparature is 23 celcius T = 23 + 273K = 296K
The pressure of the gas P = 755 torr
Calculating the moles of CaC2 n = 1.53g x 64.0994 mol/g = 0.023869 moles
PV = nRT
V = nRT / P => V = (0.023869 mol) x (62.3636 L Torr / K mol) x (296 K) / 755 torr
Volume of C2H2 = 0.587 L</span>
The answer is D. CaCl2 and H2O
