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victus00 [196]
3 years ago
7

Magnesium (24.48g) reacts with hydrochloric acid (xg) to produce hydrogen gas (2.04g) and magnesium chloride (96.90g). How much

hydrogen chloride was used in the reaction?
Chemistry
2 answers:
vovangra [49]3 years ago
6 0

Answer:

74.46

Explanation:

i did the k-12 thing just 4 u mamas :0

andriy [413]3 years ago
4 0

Answer:

Mass = 73.73 g

Explanation:

Given data:

Mass of Mg used = 24.48 g

Mass of HCl used = ?

Mass of hydrogen gas produced = 2.04 g

Mass of Magnesium chloride produced = 96.90 g

Solution:

Chemical equation:

Mg + 2HCl   →    MgCl₂ + H₂

Number of moles of Mg:

Number of moles = mass/ molar mass

Number of moles = 24.48 g/ 24.305 g/mol

Number of moles = 1.01 mol

Now we will compare the moles of Mg with HCl from balance chemical equation.

                              Mg             :            HCl

                               1                ;               2

                            1.01              :           2/1× 1.01 = 2.02 mol

Mass of HCl react:

Mass = number  of moles × molar mass

Mass =  2.02 ×  36.5 g/mol

Mass = 73.73 g

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