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Thepotemich [5.8K]
3 years ago
6

200 garms into kilogram​

Physics
2 answers:
Ad libitum [116K]3 years ago
7 0
0.2 kilogram
Divide the mass value by 1000
lana66690 [7]3 years ago
6 0

Answer:

200/1000=0.2kg hope ur help and mark me brainlist

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The term “good mother dinosaurs” is a term given to a type of dinosaur called Maiasaura which lived in the Upper Cretaceous Period, about 76.7 million years ago. This term is given<span> to the Maiasaura because of the meaning of its name "Maia". This name means "good mother" because this type of dinosaur found near of the nest of eggs and embryos.</span>
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4 years ago
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A conveyor belt at a recycling plant launches bottles and bottle caps into the air, so that an automatic image recognition devic
dem82 [27]

(a) The initial speed at which the bottles are launched is 4.27 m/s.

(b) The horizontal displacement at which the bottle land is 1.75 m.

<h3>Initial speed of the bottle</h3>

The initial speed of the bottle is calculated as follows;

T = \frac{2usin\theta}{g}

where;

  • T is time of flight
  • u is the initial speed

2usinθ = Tg

u = Tg/(2sinθ)

u = (0.5 x 9.8)/(2 x sin35)

u = 4.27 m/s

<h3>Horizontal displacement of the bottle</h3>

X = u²sin(2θ)/g

X = (4.27² x sin(70))/(9.8)

X = 1.75 m

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6 0
2 years ago
Multiple choice 1. which of earth's spheres contains mountains, valleys, and other landscapes? (1 point
ycow [4]
Here are the answers:
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2. Both ice and wind (glaciers, and really strong winds)
3. Water
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5. The rotating Earth
6. one year
7. The equator
8. It depends on how much of the sunlit side of the Moon faces the Earth
9. When an object in space comes between the Sun and a third object
10. D<span>ifferences in how much the Moon and the Sun pull on different parts of Earth 
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12. a. True

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4 0
3 years ago
two small spheres spaced 35cm apart have equal charge how many excess elecotrons must be present on each sphere if the magnitude
Maksim231197 [3]

Answer:

Number of electrons, n = 395.47

Explanation:

It is given that,

Force between two spheres, F=2.2\times 10^{-21}\ N

Distance between spheres, r = 35 cm = 0.35 m

A force of repulsion is acting on the spheres. It is given by :

F=k\dfrac{q^2}{r^2}

q^2=\dfrac{F.r^2}{k}

q^2=\dfrac{2.2\times 10^{-21}\ N\times (0.35\ m)^2}{9\times 10^9\ Nm^2/C^2}

q^2=2.99\times 10^{-32}

q=1.72\times 10^{-16}\ C

Let n is the number of electrons on the spheres. So,

q = n e

n=\dfrac{q}{e}

n=\dfrac{1.72\times 10^{-16}}{1.6\times 10^{-19}}

n = 395.47

So, the the number of excess electrons on the spheres are 395.47. Hence, this is the required solution.

8 0
3 years ago
You are pushing a box toward your friend with a force of 15 N, and your friend is pushing the box toward you with a force of 30
sleet_krkn [62]

Answer:

A. Net force is 15 N.

B. The answer is given below.

Explanation:

The following data were obtained from the question:

Force applied by you (Fᵧ) = 15 N

Force applied by your friend (Fբ) = 30 NForce applied by you (Fᵧ) = 15 N

Force applied by your friend (Fբ) = 30 N

Net force (Fₙ) =?

A. Determination of the net force.

Force applied by you (Fᵧ) = 15 N

Force applied by your friend (Fբ) = 30 N

Net force (Fₙ) =?

Fₙ = Fբ – Fᵧ

Fₙ = 30 – 15

Fₙ = 15 N

Thus, the net force acting on the box is 15 N.

B. From the question given above, we can conclude that the box will move towards you because the force applied by your friend is greater than yours.

4 0
3 years ago
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