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makkiz [27]
3 years ago
5

Two substances A and B, initially at different temperatures, are thermally isolated from their surroundings and allowed to come

into thermal contact. The mass of substance A is twice the mass of substance B, but the specific heat capacity of substance B is four times the specific heat capacity of substance A. Which substance will undergo a larger change in temperature?
Chemistry
1 answer:
Elden [556K]3 years ago
3 0

Answer:

B

Explanation:

For solving this we need a heat balance

Q_{a} = Q_{b}\\m_{a}*C_{a}*\Delta T_{a} = m_{b}*C_{b}*\Delta T_{b}

By changing the corresponding relations, we have

m_{a}*C_{a}*\Delta T_{a} = \frac{1}{2}m_{a}*4C_{a}*\Delta T_{b} \\\\\\

By cancelling similar factor, we obtain

\Delta T_{a} = 2 \Delta T_{b}\\\frac{\Delta T_{a}}{\Delta T_{b}} = 2\\

Which means that the change of temperature in A is twice the change of B

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Which conversion factor correctly shows the relationship between moles and representative particles?
strojnjashka [21]
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3 years ago
A 200. gram sample of a salt solution contains 0.050 grams of NaCl. What is the concentration of the
wariber [46]

Answer:

2.5 × 10² ppm

Explanation:

Step 1: Given data

  • Mass of NaCl: 0.050 g
  • Mass of the sample: 200. g

Step 2: Convert 0.050 g to μg

We will use the conversion factor 1 g = 10⁶ μg.

0.050 g × 10⁶ μg/1 g = 5.0 × 10⁴ μg

Step 3: Calculate the concentration of NaCl in ppm

The concentration of NaCl in ppm is equal to the micrograms of NaCl per gram of the sample.

5.0 × 10⁴ μg NaCl/200. g = 2.5 × 10² ppm

3 0
3 years ago
Archeologists can determine the age of artifacts made of wood or bone by measuring the amount of the radioactive isotope 14C pre
Ahat [919]

Answer: The age of the tool is 15539 years

Explanation:

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t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  

t = age of sample

a = let initial amount of the reactant = 100

a - x = amount left after decay process = \frac{15.5}{100}\times 100=15.5  

a) for completion of half life:

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b) for 15.5 % of original amount

t=\frac{2.303}{0.00012}\log\frac{100}{15.5}

t=15539years

Thus age of the tool is 15539 years

8 0
3 years ago
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