Answer:
c. V = k Q1 * Q2 / R1 potential energy of Q1 and Q2 separated by R
V2 / V1 = (R1 / R2) = 1/4
V2 = V1 / 4
Answer:
This is the midline or the medium which is the exact middle of the graphs minimum and maximum points(which are the amplitude)
Answer:
D. 66.4
Explanation:
So this problem uses SOHCAHTOA or the three trig functions.
Specifically this uses cosine, because it has an adjacent and a hypotenuse.
First you would determine what to do on the calculator, and since the problem is saying so, use the inverse cosine button. This will give you a angle measure from the decimal.
On a calculator, type in cos^-1(6/15). I used 6/15 because cosine is adjacent over hypotenuse. This will give you 66.4, which is D on the answers.
Answer:
Because the sodium bicarbonate does not separate into sodium, hydrogen, carbon and oxygen
Explanation:
The components of sodium bicarbonate differ in their solubilities in water.baking soda is sodium bicarbonate.
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)
<u>Explanation:</u>
Given data
Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s
The equation format is written as,
y = A sin ( k x – ω t)
We need the value of A, k, x -ω t
<u>1. Find the k value</u>
v = f ×λ
330 = 440×λ
k = 2π×λ
k = 880 π /330 m-1
440 ×2π = w
<u>2. Find the ω value</u>
f×2π =ω
ω
= 880 π s-1
<u>3. Find the A value</u>
we get A value from the given data
A = 0.02 m
By the formula,
y = A sin ( k x – ω t)
Substitute the values we get the equation,
y = 0.02 sin (880π/330 x – 880 πt)
The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)