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2 years ago

The position-time equation for a cheetah chasing an antelope is:

Physics

1 answer:

pochemuha2 years ago

4 0

Answer:

x = 1.6 + 1.7 t^2 omitting signs

a) at t = 0 x = 1.6 m

b) V = d x / d t = 3.4 t

at t = 0 V = 0

c) A = d^2 x / d t^2 = 3.4 (at t = 0 A = 3.4 m/s^2)

d) x = 1.6 + 1.7 * (4.4)^2 = 34.5 (position at 4.4 sec = 34.5 m)

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Newton's third law states that for every action force there is an equal and opposite reaction force. An idiot in your class says

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A. Because the third laws say that for every action force the is an equal and opposite reaction force

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3 years ago

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What is the value of work done on an object when a 70–newton force moves it 9.0 meters in the same direction as the force?

slava [35]

Answer:

630 J

Explanation:

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3 years ago

Plz explain the answers with steps and a little bit of explanation. I really need the answers for my exam tomorrow! Please help

DochEvi [55]

Here's what you need to memorize for your exam tomorrow.

Distance = (speed) x (time) .

That's it. Memorize it.

-- If the question wants you to find speed, use it exactly in that form.

-- If the question wants you to find speed, then divide each side by (time)
and it says

. Time = (distance) / (speed) .

-- If the question wants you to find time, then divide each side by speed,
and it says

. Time = (distance) / (speed) .

So if you memorize that one equation ... Distance = (speed) x (time) ...
you can solve ANY problem to find distance, speed, or time.

On the sheet in the picture . . . . .

#2). The question is "How long ?". That's TIME that you have to find.
Use the equation in the form of

. TIME = (distance) / (speed)

. = (60 km) / (48 km/h)

. = 1.25 hours .

#3). This one wants you to find SPEED. Use the equation in the form of

. SPEED = (distance) / (time)

but be careful. The time has to be in hours. 55 minutes = 55/60 of an hour.

. SPEED = (distance) / (time)

. = (60 km) / (55/60 hour)

. = (60 x 60 km) / (55 hour)

. = 65.45 km/hr .

#4). This one wants you to find TIME. (It says "How long ?".)

It's two trips, so you have to find the time for each trip.

First trip: TIME = (distance)/(speed) = (24 km)/(65 km/hr) = 0.369 hr

Second trip: TIME = (distance)/(speed) = (50 km)/(80 km/hr) = 0.625 hr

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3 years ago

Use the energy equation from this week’s notes, your answer from

slamgirl [31]

An energy equation is a chemical equation which involves the energy that is evolved or absorbed in the reaction.

<h3>What is energy?</h3>

The term energy refers to the ability to do work. An energy equation is a chemical equation which involves the energy that is evolved or absorbed in the reaction.

This question is incomplete as the former energy equation is not shown. However, such equations can be used to know an endothermic or exothermic reaction.

Learn more about energy: brainly.com/question/1932868?

#SPJ4

3 0

2 years ago

What is the potential energy of two charges of +4.6 μC and +1.0 μC that are separated by a distance of 10.0 cm?

Artist 52 [7]

Answer:

U = 0.413 J

Explanation:

the potential energy between two charges q1 and q2 is given by the following formula:

$U=k\frac{q_1q_2}{r}$ (1)

k: Coulomb's constant = 8.98*10^9 NM^2/C^2

q1: first charge = 4.6 μC = 4.6*10^-6 C

q2: second charge = 1.0 μC*10^-6 C

r: distance between charges = 10.0 cm = 0.10 m

You replace the values of all variables in the equation (1):

$U=(8.98*10^9Nm^2/C^2)\frac{(4.6*10^{-6}C)(1.0*10^{-6}C)}{0.10m}=0.413\ J$

Hence, the energy between charges is 0.413 J

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3 years ago