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Gala2k [10]
3 years ago
5

What is cos(6)? A. 0.99 B. 0.60 C. 0.10 D. 0.06

Physics
2 answers:
Harrizon [31]3 years ago
4 0
A . 0.99 hopefully that’s correct
julsineya [31]3 years ago
3 0

Answer:

A. 0.99 :)

Explanation:

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What is the efficacy of a 60.0 W incandescent lightbulb that produces 830 lumens?
Alex17521 [72]

η = 13.8 lm/W. The luminous efficacy of a incandescent lightbulb that produces 830 lumens and consumed a power of 60 W is 13.8 lm/W.

The luminous efficacy of a light source is the relationship between the luminous flux (in lumens) emitted by a light source and the power (in watts). The luminous efficacy of a light source or luminous efficiency measures the part of electrical energy that is used to illuminate and is obtained by dividing the luminous flux emitted by the electrical power consumed. Luminous efficiency is expressed in lumens per watt (lm / W). It is given by the relation:

η = F / P.  Where F is the luminous flux, and P is the power consumed by the light source.

The efficacy of a 60.0 W incandescent lightbulb that produces 830 lm is:

η = 830 lm / 60 W

η = 13.8 lm/W

7 0
3 years ago
If you measure a change in temperature, then the _____.
kherson [118]

Answer:

C. total heat energy of the substance has increased

Explanation:

This is because when there is a change in temperature, the heat energy of a substance either increases or decreases. If the temperature increases, its heat energy increases and if its temperature decreases, its heat enery decreases.

6 0
3 years ago
Interactive LearningWare 8.1 reviews the approach that is necessary for solving problems such as this one. A motorcyclist is tra
STALIN [3.7K]

Answer:

The angular displacement of each wheel is 269.92 rad

Explanation:

Given:

Angular acceleration \alpha = 6.10 \frac{rad}{s^{2} }

Time to pass cyclist t = 4.36 s

Angular velocity \omega _{f} = 75.2 \frac{rad}{s}

According to the equation of kinematics,

  \omega _{f} = \omega _{i} + \alpha   t

   \omega _{i} = \omega _{f} - \alpha   t

   \omega _{i} = 75.2 - 6.10 \times 4.36

  \omega _{f} = 48.60 \frac{rad}{s}

For finding angular displacement,

    \omega _{f} ^{2}  - \omega _{i} ^{2}  = 2 \alpha  \theta

Where \theta = angular displacement,

  \theta  = \frac{\omega _{f}^{2} - \omega _{i} ^{2}  }{2\alpha }

  \theta  = \frac{5655.04 - 2361.96  }{2\times 6.10 }

  \theta = 269.92 rad

Therefore, the angular displacement of each wheel is 269.92 rad

8 0
3 years ago
What is the maximum speed (in units of m/s) with which a car can round a
IrinaK [193]

Answer:

B)  15.5 m/s

Explanation:

r = 60m

μs = 0.4

using the formula max V = √r*g*μs (flat roadway)

v = sqrt(60 * 10 * 0.4)

v = 15.5 m/s

5 0
3 years ago
An asteroid has acquired a net negative charge of 149 C from being bombarded by the solar wind over the years, and is currently
bearhunter [10]

Answer:

93.125 × 10^(19)

Explanation:

We are told the asteroid has acquired a net negative charge of 149 C.

Thus;

Q = -149 C

charge on electron has a value of:

e = -1.6 × 10^(-19) C

Now, for us to determine the excess electrons on the asteroid, we will just divide the net charge in excess on the asteroid by the charge of a single electron.

Thus;

n = Q/e

n = -149/(-1.6 × 10^(-19))

n = 93.125 × 10^(19)

Thus, it has 93.125 × 10^(19) more electrons than protons

5 0
3 years ago
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