All categories

3 years ago

What is cos(6)? A. 0.99 B. 0.60 C. 0.10 D. 0.06

Physics

2 answers:

Harrizon [31]3 years ago

4 0

A . 0.99 hopefully that’s correct

julsineya [31]3 years ago

3 0

Answer:

A. 0.99 :)

Explanation:

You might be interested in

8. Which of the following is not a goal of the Clean Water Act? (1 point)

ankoles [38]

Answer: D allowing businesses to release industrial wastes into rivers

4 0

3 years ago

A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. the coefficients of static and kinetic friction

elena-14-01-66 [18.8K]

My dude, have u heard of photomatg

3 0

3 years ago

Read 2 more answers

The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in

Alinara [238K]

Answer:

The angular separation between the red and violet components of the spectrum that emerges from the glass is 1.72°

Explanation:

Given:

Refractive index for red light $n _{1} = 1.620$

Refractive index for violet $n' _{1} = 1.660$

Refractive index for air $n_{2} = 1$

Incident angle $\theta _{1} =$ 28.30°

According to the snell's law,

$n_{1} \sin \theta _{1} = n_{2} \sin \theta _{2}$

For red light,

$1.620 \times \sin 28.30 = 1 \sin \theta _{2}$

Where $\theta _{2} =$ transmitted angle for red light

$\theta _{2} =$ 50.18°

For violet light,

$1.660 \times \sin 28.30 = 1 \sin \theta' _{2}$

Where $\theta' _{2} =$ transmitted angle for violet light

$\theta' _{2} =$ 51.9°

Angular separation between red and violet light is given by,

$\theta ' _{2} - \theta _{2} = 51.9 -50.18 =$ 1.72°

Therefore, the angular separation between the red and violet components of the spectrum that emerges from the glass is 1.72°

6 0

3 years ago

What is wrong about the picture below

Oliga [24]

what even is that ??

4 0

3 years ago

For a railgun, determine the current required to accelerate a 1000kg space vehicle to earths escape velocity on 10km of track wi

Troyanec [42]

Answer:

the current is 15.68 × $10^{5}$ A

Explanation:

mass = 1000 kg

magnetic fied = 2T

rail separation = 2m

escape velocity is 11.2km/s = 11.2 × $10^{3}$ m/s

distance = 10 km = $10^{4}$ m

to find out

determine the current

solution

we know force F = I×L×B

here I is current and L is rail separation and B is magnetic field

so F = I ×2×2 = 4 I

acceleration is a = $\frac{F}{mass}$

a = $\frac{4I}{1000}$ m/s²

so equation of motion

v²-u² = 2 a S

here u is initial velocity and S is distance and a is acceleration and v is final velocity

11.2 × $10^{3}$ - 0 = 2× $\frac{4I}{1000}$ × $10^{4}$

solve we get I

I = 15.68 × $10^{5}$ A

so the current is 15.68 × $10^{5}$ A

4 0

3 years ago