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ololo11 [35]
3 years ago
7

What is our cosmic address??

Chemistry
2 answers:
MAVERICK [17]3 years ago
4 0
Sydney Observatory, 1003 Upper Fort St, Millers Point, Sydney, NSW, Australia
murzikaleks [220]3 years ago
3 0
Our full Cosmic Address: Sydney Observatory, 1003 Upper Fort St, Millers Point, Sydney, NSW, Australia, Earth, The Solar System, Orion Arm, The Milky Way, Local Group, Virgo Cluster, Virgo Super-Cluster, Universe … One?
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When two species A and B form an electron-pair bond and A does not provide its electrons for bonding, the bond present between A
vichka [17]

Answer:

Ionic

Explanation:

If A does not have electron to bond, it just receives one electron from B.

It can´t be covalent because A don´t have any electrons to bond with B.

5 0
3 years ago
Capsaicin, the compound that gives the hot taste to chili peppers, has the formula C18H27NO3. Its molar mass is 305.42 g/mol. Ca
stellarik [79]
Molar mass = 305.42 g/mol

C = ( 12 x 18 / 305.42 ) x 100 => 70.72 % of C

H = ( 1 x 27 / 305.42 ) x 100 => 8.84 % of H

N = ( 14 x 1 / 305.42 ) x 100 => 4.58 % of N

O = ( 16 x 3 / 305.42) x 100 => 15.71% of O

hope this helps!
5 0
3 years ago
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The pH of a 0.150 molar solution of a weak acid is 4.10. What is the pKa of the acid?
Kamila [148]
Answer: 4.21×10⁻⁸

Explanation:


1) Assume a general equation for the ionization of the weak acid:

Let HA be the weak acid, then the ionization equation is:

HA ⇄ H⁺ + A⁻

2) Then, the expression for the ionization constant is:

Ka = [H⁺][A⁻] / [HA]

There, [H⁺] = [A⁻], and [HA] = 0.150 M (data given)


3) So, you need to determine [H⁺] which you do from the pH.

By definition, pH = - log [H⁺]

And from the data given pH = 4.1


⇒ 4.10 = - log [H⁺] ⇒ [H⁺] = antilog (- 4.10) = 7.94×10⁻⁵

4) Now you have all the values to calculate the expression for Ka:

ka = 7.94×10⁻⁵ × 7.94×10⁻⁵ / 0.150 = 4.21×10⁻⁸
3 0
4 years ago
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What is the empirical formula for a compound that is 82.2% nitrogen and 17.8% hydrogen?
Stolb23 [73]
Empirical formula=CH3
3 0
3 years ago
Filtration definition 
dezoksy [38]

Answer:

the action or process of filtering something.

8 0
3 years ago
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