Looks to me like C and O are virtually equal and H is double those, so:
CH_20, which is the empirical formula for carbohydrates.
<u>Answer:</u> The amount of energy released per gram of
is -71.92 kJ
<u>Explanation:</u>
For the given chemical reaction:

The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28reactant%29%7D%5D)
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(5\times \Delta H^o_f_{(B_2O_3(s))})+(9\times \Delta H^o_f_{(H_2O(l))})]-[(2\times \Delta H^o_f_{(B_5H_9(l))})+(12\times \Delta H^o_f_{(O_2(g))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%285%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28B_2O_3%28s%29%29%7D%29%2B%289%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28H_2O%28l%29%29%7D%29%5D-%5B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28B_5H_9%28l%29%29%7D%29%2B%2812%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%29%5D)
Taking the standard enthalpy of formation:

Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(5\times (1271.94))+(9\times (-285.83))]-[(2\times (73.2))+(12\times (0))]\\\\\Delta H^o_{rxn}=-9078.57kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%285%5Ctimes%20%281271.94%29%29%2B%289%5Ctimes%20%28-285.83%29%29%5D-%5B%282%5Ctimes%20%2873.2%29%29%2B%2812%5Ctimes%20%280%29%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D-9078.57kJ)
We know that:
Molar mass of pentaborane -9 = 63.12 g/mol
By Stoichiometry of the reaction:
If 2 moles of
produces -9078.57 kJ of energy.
Or,
If
of
produces -9078.57 kJ of energy
Then, 1 gram of
will produce =
of energy.
Hence, the amount of energy released per gram of
is -71.92 kJ
Answer: The mass of oxygen that combines with nitrogen will be 2.272g.
Explanation:
Answer:
Coefficient in front of the
in the balanced equation - 1
Explanation:
The unbalanced Chemical equation is shown below as:-
On the left hand side,
There are 1 boron atom and 3 fluorine atoms and 1 sodium and hydrogen atoms.
On the right hand side,
There are 2 boron atoms and 6 hydrogen atoms and 1 sodium and fluorine atoms.
Thus,
leftside,
must be multiplied by 2 to balance boron and right side,
must be multiplied by 6 to balance fluorine. Left side,
must be multiplied by 6 to balance sodium and hydrogen atoms.
Thus, the balanced reaction is:-
<u>Coefficient in front of the
in the balanced equation - 1</u>