Answer:
London dispersion forces
Explanation:
The London dispersion force is a temporary attractive force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles.
Answer:
l = 0 → s = 2 electrons;
l = 1 → p = 6 electrons;
l = 2 → d = 10 electrons;
l= 3 → f = 14 electrons.
Explanation:
For the quantum theory, the probability to find an electron is higher in the space region called orbital. It's impossible to determine where the electron is and his velocity at the same time (uncertainty principle). So, the theory determines four quantum numbers to characterize an electron, so it's easy to identify it:
- n is the principal quantum number and identify the shell where the electron is. It varies from 1 to 7 and is represented by the letters K, L, M, N, O, P, and Q;
- l is the azimuthal quantum number and identify the subshell (or sublevel) where the electron is. It varies from 0 to 3 and is represented by the letters s, p, d, and f;
- ml is the magnetic quantum number, and it represents the orbital. It varies from -l to +l, passing by 0. Each orbital can have at least 2 electrons;
- ms is the spin number and represents the spin of the electrons. It can be +1/2 or - 1/2.
Then, the sublevel s (l= 0) only has 1 orbital (ml = 0) so, it can have ate least 2 electrons; the sublevel p (l= 1) has 3 orbitals (ml = -1, ml= 0, ml = +1), so it can have at least 6 electrons; the sublevel d (l = 2) has 5 orbitals (ml = -2, ml = -1, ml = 0, ml = +1, ml = +2), so it can have at least 10 electrons; and the sublevel f (l = 3) has 7 orbitals (ml = -3, ml = -2, ml = -1, ml = 0, ml = +1, ml = +2, ml = +3), so it can have at least 14 electrons.
830 mL
The volume of an 2.3 m solution with 212 grams of calcium chloride (cacl2) dissolved is 830 mL.
The solution has a concentration of 2.3 mol/L.
<h3>a) Moles of CaCl2</h3>
Molar mass of CaCl2 = 110.98 g/mol
Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)
= 1.910 mol CaCl2
<h3>b) Volume of solution</h3>
V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution
= 830 mL solution
<h3>How much CaCl2 is there in the solution by molarity?</h3>
- The number of moles is 0.125 x 2 = 0.25 mol since the molarity is 2.0M.
- To get the answer of 27.745 g, simply multiply this by the molar mass of calcium chloride, which is 110.98 g/mol.
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Answer:
a) V = 1.542 E11 ft³
b) V = 4367011968 m³
c) V = 1.1535 E12 us gal
Explanation:
Acre surface is defined as 66 by 660 feet at a depth of one foot:
⇒ Vacre-foot = 66ft*660ft*1ft = 43560 ft³
lake:
a) V = 3.54 E6 acre-feet * ( 43560 ft³ / acre-foot ) = 1.542 E11 ft³
b) V = 1.542 E11 ft³ * ( 0.02832m³ / ft³ ) = 4367011968 m³
c) V = 1.542 E11 ft³ * ( 7.48052 us gal/ft³ ) = 1.1535 E12 us gal
It's in the periodic table.
See the attached picture. The number below 'Zn' is the molar mass. The closest answer choice is 65.38
