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enyata [817]
2 years ago
5

Someone help me please i need to finish this

Physics
2 answers:
Ilya [14]2 years ago
8 0

Answer:

D. A zinc Zn contains 30 protons inside the nucleus and 30 electron outside the nucleus

gavmur [86]2 years ago
5 0

Answer:

the last option is correct

Explanation:

see I won't explain all the points but will tell you the concept being used.

  • protons and neutrons are inside the nucleus in an atom while the electrons are outside the nucleus.

  • the mass number of an atom is equal to the sum of number of electrons and neutrons in an atom
  • atomic number is equal to the number of electrons which is equal to the number of protons in an atom
  • no. of electrons/ protons is always less than that of neutrons and they're almost equal( a large difference ain't obtained between the number of electrons and that of neutrons.

since, the rest of the options are violating the above rules they're incorrect

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If a woman weighs 125 lb, her mass expressed in kilograms is x kg, where x is
adelina 88 [10]
The first thing you should know to solve this problem is the conversion of pounds to kilograms:
 1lb = 0.45 Kg
 We can solve this problem by a simple rule of three
 1lb ---> 0.45Kg
 125lb ---> x
 Clearing x we have:
 x = ((125) / (1)) * (0.45) = 56.25 Kg.
 Answer
 her mass expressed in kilograms is 56.25 Kg.
3 0
2 years ago
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A 5000kg freight car moving at 2 m/s East collides with a 10,000kg freight car at rest. Upon collision, they got stuck and moved
mr_godi [17]

Answer:

A

Explanation:

6 0
2 years ago
Where is the Oort cloud located?
sergiy2304 [10]

Answer: C

Explanation: just did it

8 0
3 years ago
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A car is pushed with a force of 450 N for 19.4 seconds. What impulse was applied to the car?​
harina [27]

Answer:

impulse = 8820 kg·\frac{m}{s} or 8820 N·s

Explanation:

Impulse J is equal to the average force F_{av} multiplied by the elapsed time Δt or in equation form, J = F_{av}Δt

As long as your force of 450 N is constant then that value is your average force F_{av} and your elapsed time is 19.4 seconds.

Multiply these values.

You will get an impulse of 8820 kg·\frac{m}{s} or 8820 N·s.

6 0
2 years ago
A 35.9 g mass is attached to a horizontal spring with a spring constant of 18.4 N/m and released from rest with an amplitude of
lidiya [134]

Answer:

7.74m/s

Explanation:

Mass = 35.9g = 0.0359kg

A = 39.5cm = 0.395m

K = 18.4N/m

At equilibrium position, there's total conservation of energy.

Total energy = kinetic energy + potential energy

Total Energy = K.E + P.E

½KA² = ½mv² + ½kx²

½KA² = ½(mv² + kx²)

KA² = mv² + kx²

Collect like terms

KA² - Kx² = mv²

K(A² - x²) = mv²

V² = k/m (A² - x²)

V = √(K/m (A² - x²) )

note x = ½A

V = √(k/m (A² - (½A)²)

V = √(k/m (A² - A²/4))

Resolve the fraction between A.

V = √(¾. K/m. A² )

V = √(¾ * (18.4/0.0359)*(0.395)²)

V = √(0.75 * 512.53 * 0.156)

V = √(59.966)

V = 7.74m/s

8 0
2 years ago
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