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3 years ago

What do we mean by thrust?

Physics

1 answer:

Lubov Fominskaja [6]3 years ago

3 0

Answer:

the answer is push example: she thrust her hand into her pocket

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Find the moment of inertia about each of the following axes for a rod that is 0.360 {cm} in diameter and 1.70 {m} long, with a m

mamaluj [8]

The complete question is;

Find the moment of inertia about each of the following axes for a rod that is 0.36 cm in diameter and 1.70m long, with a mass of 5.00 × 10 ^(−2) kg.

A) About an axis perpendicular to the rod and passing through its center in kg.m²

B) About an axis perpendicular to the rod and passing through one end in kg.m²

C) About an axis along the length of the rod in kg.m²

Answer:

A) I = 0.012 kg.m²

B) I = 0.048 kg.m²

C) I = 8.1 × 10^(-8) kg.m²

Explanation:

We are given;

Diameter = 0.36 cm = 0.36 × 10^(−2) m

Length; L = 1.7m

Mass;m = 5 × 10^(−2) kg

A) For an axis perpendicular to the rod and passing through its center, the formula for the moment of inertia is;

I = mL²/12

I = (5 × 10^(−2) × 1.7²)/12

I = 0.012 kg.m²

B) For an axis perpendicular to the rod and passing through one end, the formula for the moment of inertia is;

I = mL²/3

So,

I = (5 × 10^(−2) × 1.7²)/3

I = 0.048 kg.m²

C) For an axis along the length of the rod, the formula for the moment of inertia is; I = mr²/2

We have diameter = 0.36 × 10^(−2) m, thus radius;r = (0.36 × 10^(−2))/2 = 0.18 × 10^(−2) m

I = (5 × 10^(−2) × (0.18 × 10^(−2))^2)/2

I = 8.1 × 10^(-8) kg.m²

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3 years ago

A load of bricks is being lifted by a crane at a steady velocity of 5.0m/s when one bricks falls off 6.0 m above the ground

Ganezh [65]

LOOK OUT BELOW ! ! !

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3 years ago

A large water tank is 3.75 m high and filled to the brim, the top of the tank open to the air. A small pipe with a faucet is att

Degger [83]

Answer:

7.16 m /s

Explanation:

The depth of the small pipe attached with the side wall of tank from the surface of water

h =( 3.1 - .48 )m

= 2.62 m

velocity of flow of water= √ 2 g h

= √ 2 x 9.8 x 2.62

= 7.16 m /s

#need any question answered within secs/mins, hit me up and I got you!

#branilest

:) <3

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3 years ago

A bullet has a speed of 500 m/s as it leaves a rifle. If it is fired horizontally from a cliff 12m above a lake, how far does th

dem82 [27]

Because you don’t have it

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3 years ago

While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th

san4es73 [151]

Answer:

a. $v=3.03\frac{m}{s}$

b. $a_c=0.71\frac{m}{s^2}$

c. $\frac{W_{top}}{W}=0.93$

d. $\frac{W_{bot}}{W}=1.07$

Explanation:

a. The speed is the distance travelled divided by the time:

$v=\frac{2\pi r}{T}\\v=\frac{2\pi(13m)}{27s}\\v=3.03\frac{m}{s}$

b. The magnitud of the centripetal acceleration is given by:

$a_c=\frac{v^2}{r}\\a_c=\frac{(3.03\frac{m}{s})^2}{13m}\\a_c=0.71\frac{m}{s^2}$

c. According to Newton's second law, at the top we have:

$\sum F_{top}:W-W_{top}=ma_c\\W_{top}=mg-ma_c\\W_{top}=m(g-a_c)\\W_{top}=m(9.8\frac{m}{s^2}-0.71\frac{m}{s^2})\\W_{top}=m(9.09\frac{m}{s^2})\\\frac{W_{top}}{W}=\frac{m(9.09\frac{m}{s^2})}{m(9.8\frac{m}{s^2})}\\\frac{W_{top}}{W}=0.93$

d. According to Newton's second law, at the bottom we have:

$\sum F_{bot}:-W+W_{bot}=ma_c\\W_{bot}=mg+ma_c\\W_{bot}=m(g+a_c)\\W_{bot}=m(9.8\frac{m}{s^2}+0.71\frac{m}{s^2})\\W_{bot}=m(10.51\frac{m}{s^2})\\\frac{W_{bot}}{W}=\frac{m(10.51\frac{m}{s^2})}{m(9.8\frac{m}{s^2})}\\\frac{W_{bot}}{W}=1.07$

3 0

3 years ago

What do we mean by thrust?​

What do we mean by thrust?