I hope you are referring to Newton's Laws of Motion by "Newton's Law".
There are three laws quoted by the great physicist of all time Sir Isaac Newton.
These laws are the building-blocks of the field of the Physics known as Classical Physics or Classical Mechanics.
Law 1. If no force applied externally, then a body in rest will always be in rest and a body in motion will continue to move in a straight line with a uniform velocity.
Law 2. The rate of change of momentum is directly proportional to the force applied and the direction of motion is always in the direction of the force applied.
Law 3. Every action has an equal and opposite reaction.
The Law 1 is also called the law of Inertia.
From the 2nd law, we can derive the equation of force, that is F =m.a (m = mass; a = acceleration)
Answer:
Traveling with a constant velocity means you're going at the same speed in the same direction continuously. If you have a constant velocity, this means you have zero acceleration. ... If you travel with a constant acceleration, your velocity is always changing, but it's changing by a consistent amount each second.
<span>The purpose of pumping is to increase overall velocity. The person drops down into a crouch while traversing the more-or-less flat bottom of the U-shaped pipe or bowl. Then, as he enters the sloped part of the ramp or bowl, called the transition, he straightens his legs and rises up. By raising his center of mass just at the beginning of the arc, the person gains energy and thereby increases his speed.</span>
Answer:
0.3 m
Explanation:
Initially, the package has both gravitational potential energy and kinetic energy. The spring has elastic energy. After the package is brought to rest, all the energy is stored in the spring.
Initial energy = final energy
mgh + ½ mv² + ½ kx₁² = ½ kx₂²
Given:
m = 50 kg
g = 9.8 m/s²
h = 8 sin 20º m
v = 2 m/s
k = 30000 N/m
x₁ = 0.05 m
(50)(9.8)(8 sin 20) + ½ (50)(2)² + ½ (30000)(0.05)² = ½ (30000)x₂²
x₂ ≈ 0.314 m
So the spring is compressed 0.314 m from it's natural length. However, we're asked to find the additional deformation from the original 50mm.
x₂ − x₁
0.314 m − 0.05 m
0.264 m
Rounding to 1 sig-fig, the spring is compressed an additional 0.3 meters.
Answer:
Explanation:
We have to use the centripetal force equation
we need the radious so we have to isolate "r" and we get
replacing m=65 kg, v= 4.1 m/s and Fc=455N we get
The radius of the amusement park chamber is 2.4m
