Answer:
C = 1.01
Explanation:
Given that,
Mass, m = 75 kg
The terminal velocity of the mass,
Area of cross section,
We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,
R = W
or
Where
is the density of air = 1.225 kg/m³
C is drag coefficient
So,
So, the drag coefficient is 1.01.
Answer:
Height = 53.361 m
Explanation:
There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12
From the given information we make the following summary
= 0m/s
= t
= 43.12m/s
= (t-2.2)s
The distance by the first balloon is
where
a = 9.8m/s2
Inputting the values
The distance traveled by the second balloon
Inputting the values
simplifying
Substituting D of the first balloon into the D of the second balloon and solving
Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment