The electrical equivalent of one horsepower is 746 watts in the International System of Units (SI), and the heat equivalent is 2,545 BTU (British Thermal Units) per hour. Another unit of power is the metric horsepower, which equals 4,500 kilogram-metres per minute (32,549 foot-pounds per minute), or 0.9863 horsepower.
Full outer shell of electrons, they are colorless and odorless ,their melting and boiling points are close together which gives them very narrow liquid range
Answer:
D. is greater for turbulent flow than for laminar flow
Explanation:
what is friction drag?
- friction drag is a phenomenon experienced when a body moves through a fluid. A practical example can be seen in the mild warmth we experience rubbing the palm's of one's hand together only in this case we are dealing with a solid body and a fluid (e.g air, water). friction drag is directly proportional to the area of the surface in contact with the fluid and increases as velocity increases. We see a practical example of this when the rate at which one rubs the palms together is fast but we use the word turbulent when we are dealing with fluids. Turbulent flow creates more friction drag than laminar flow( Flow between a smooth body and fluid) due to its greater interaction with the surface of the body
- it is important to know that friction is also called viscous drag or skin drag
- I recommend Richardson and coulson vol 2 textbook, page 149, Chemical enginering fluid mechanics textbook by Ron dardy, page 341 for clearer explanation
Answer:
charge, q = ± 1.1 mC
Given:
Capacitance, 
Voltage, V = 110 V
Solution:
The charge on the capacitor plates can be calculated by using the definition of capacitance as :
q ∝ V
where
q = charge
V = potential difference or Voltage
Therefore,
q = CV
Now, charge, q :
q = 
Therefore, the charge on the positive plate is:
q = + 1.1 mC
the charge on the negative plate is:
q = - 1.1 mC
Answer:
The maximum load that this person is able to lift is 34.3 N
Explanation:
Applying the balancing torque, the expression is equal:
F₁L₁ = F₂L₂
Where
g = 9.8 m/s² = gravity
L₁ = 0.8 m
F₂ = 527 N
L₂ = 6 - 0.8 = 5.2 m
Replacing and clearing the mass m:
The maximum load that this person is able to lift is:
F = m * g = 3.5 * 9.8 = 34.3 N
