The NaOH will be used What titrant to titrate the 0. 02 m hcl phenol red solution.
Acid-base titrations may be the most typical titrations, although there are numerous more forms as well. Take a look at this illustration where sodium hydroxide is used to titrate a sample of hydrochloric acid (HCl) (NaOH). The titrant (NaOH), which is added gradually throughout the duration of the titration, has been added to the unknown solution.
Titrants are solutions with known concentrations that are added to solutions whose concentrations must be determined. The solution for whom the concentration needs to be determined is known as a titrant as well as analyte.
Therefore, the NaOH will be used as a titrant to titrate the 0. 02 m hcl phenol red solution.
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ANS: density = 13.41 g/ml
Density (d) of a substance is the mass (m) occupied by it in a given volume (v).
Density = mass/volume
i.e. d = m/v
m = (d) v -----(1)
The given equation from the plot of weight vs volume is :
y = 13.41 x ----(2)
Based on equations (1) and (2) we can deduce that the density of the metal is 13.41 g/ml
Kelvin (K) is the only scale that has a numeral value assigned to absolute zero.
Answer:
The method is accurate in the calculation of the 
Explanation:
As a first step we have to calculate the <u>average concentration </u>of
find it by the method.

Then we have to find the<u> standard deviation:</u>

For the confidence interval we have to use the formula:
μ=Average±
Where:
t=t student constant with 95 % of confidence and 5 data=2.78
μ=
± 
upper limit: 0.84
lower limit: 0.75
If we compare the limits of the value obtanied by the method (Figure 1 Red line) with the reference material (Figure 1 blue line) we can see that the values obtained by the method are within the values suggested by the reference material. So, it's method is accurate.
Answer:
derived unit. noun. a unit of measurement obtained by multiplication or division of the base units of a system without the introduction of numerical factors.
Explanation: