1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Aleksandr-060686 [28]
3 years ago
12

Adam pushes a 47 kg boat across a frozen lake. The coefficient of kinetic friction between the boat and the ice is 0.13 and the

boat acceleration at 0.6 m/s^2. Calculate the magnitude of Adams force in the boat.
Physics
1 answer:
yuradex [85]3 years ago
5 0

Answer:

The magnitude of Adams' force is 88 N

Explanation:

According to Newton's law ∑ forces in direction of motion is equal to

mass multiplied by the acceleration

There are two forces here the friction force and Adams' force

Adams' force is in direction of motion

Friction force is opposite to direction of motion

→ Friction force = μ R,

where μ is the coefficient of friction and R is the normal reaction force

of the boat

→ R = mg

where m is the mass of the boat and g is the acceleration of gravity

→ m = 47 kg , g = 9.8 m/s²

→ R = mg

Substitute the values in the rule

→ R = 47 × 9.8 = 460.6 N

→ Friction force = μ R

→ μ = 0.13 , R = 460.0 N

Substitute the values in the rule

→ Friction force = 0.13 × 460.0 = 59.878 N

→ ∑ Forces in direction of motion = mass × acceleration

→ F - Friction force = mass × acceleration

→ Friction force = 59.878 N , m = 47 kg , a = 0.6 m/s²

Substitute the values in the rule

→ F - 59.878 = 47 × 0.6

→ F - 59.878 = 28.2

Add 59.878 to both sides

→ F = 88.078 N ≅ 88 N

<em>The magnitude of Adams' force is 88 N </em>

You might be interested in
Why can people float effortlessly on the dead sea?
ahrayia [7]
There water has a lot of salt in it, so it would be denser. People float better when the water is denser.
5 0
3 years ago
NEED HELP ASAP PLEASE!
katrin [286]

Answer:

Here is the solution hope it helps:)

5 0
2 years ago
A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage to 385 kV. The secondary of
enot [183]

Answer:

a) In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new output is 86% of the old output

c) The losses in the new line are 74% the losses in the old line.

Explanation:

a) To relate the turns of primary and secondary to the ratio of voltage we have this expression:

\frac{n_1}{n_2}=\frac{V_1}{V_2}

In the old transformer the ratio of voltages was:

\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{385} =0.03117\\\\n_2=n_1/0.03117=32.1n_1

In the new transformer the ratio of voltages is:

\frac{n_1}{n_2}=\frac{V_1}{V_2}=\frac{12}{500} =0.024\\\\n_2=n_1/0.24=41.7n_1

In the new transformer there are 42 turns in the secondary per turn in the primary, while in the old transformer there were 32 turns per turn in the primary.

b) The new current ratio is

\frac{V_1}{V_2}=\frac{I_2}{I_1}=\frac{12}{500}= 0.024\\\\I_2=0.024I_1

If the old current output was 425 kV, the ratio of current was:

\frac{V_1}{V_2}=\frac{I_2}{I_1}=\frac{12}{425}= 0.028\\\\I_2=0.028I_1

Then, the ratio of the new output over the old output is:

\frac{I_{2new}}{I_{2old}} =\frac{0.024\cdot I_1}{0.028\cdot I_1}= 0.86

The new output is 86% of the old output (smaller output currents lower the losses on the transmission line).

c) The power loss is expressed as:

P_L=I^2\cdot R

Then, the ratio of losses is (R is constant for both power losses):

\frac{P_n}{P_o} =\frac{I_n^2R}{I_o^2R} =(\frac{I_n}{I_o} )^2=0.86^2=0.74

The losses in the new line are 74% the losses in the old line.

7 0
3 years ago
It took Lilly 7 seconds to ride her bike 35 meters to the end of the block.What was her speed?
Zolol [24]
<h2><em>her average speed was 5 meter p/ second </em></h2><h2><em> 18 kph</em></h2><h2><em>                                     HOPE IT HELPS (◕‿◕✿)                                   </em></h2><h2><em>                                                   SMILE!!</em></h2>
4 0
3 years ago
calculating power reach each scenario and then answer the questions scenario a 120 j of work is done in 6 seconds scenario b 160
Molodets [167]

Answer: scenario b and scenario c uses most power

Explanation:

Scenario a:

Work=120J

Time=8 seconds

Power=work ➗ time

Power=120 ➗ 8

Power=15

Power=15 watts

Scenario b:

Work=160J

Time=8 seconds

Power=work ➗ time

Power=160 ➗ 8

Power=20

Power =20 watts

Scenario c:

Work=200J

Time=10 seconds

Power= work ➗ time

Power=200 ➗ 10

Power=20

Power=20 watts

Scenario b and scenario c uses most power

4 0
3 years ago
Other questions:
  • A tuning fork is struck and is vibrating at a single frequency. If a second tuning fork with the same frequency is placed near t
    8·2 answers
  • A 0.155 kg arrow is shot upward
    14·1 answer
  • Which of the following statements about iron filings placed upon glass resting on top of a bar magnet is false?
    11·1 answer
  • Why do you think that most of your body is made of this material?
    15·1 answer
  • What acceleration results from exerting a 125N force on a 0.65kg ball?
    15·1 answer
  • A bicyclist travels the first 700 m of a trip at an average speed of 8 m/s, travels
    9·1 answer
  • How does you body reproduce
    13·1 answer
  • A lever is used to lift a heavy rock. The rock has a mass of 800 N. It requires 200 N of force to lift the rock using the lever.
    7·1 answer
  • Jupiter orbits the sun once every 4333 days in a circle of radius 7.79 * 10^10 m. What is Jupiter’s velocity
    14·1 answer
  • When a dielectric slab is inserted between the plates of one of the two identical capacitors
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!