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slamgirl [31]
2 years ago
6

Which vector goes from (-1, -3) to (-4, -1)

Physics
1 answer:
Alisiya [41]2 years ago
6 0
Its this (couldn’t write it down on here properly so i had to ss it)
Basically, it’s just the difference between the x values at the top and the difference between the Y values at the bottom.

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PLS HELP WILL MARK BRAINLIEST
MariettaO [177]

Answer:

2.835 Watts

Explanation:

P = I²R

P = 1.5² × 1.26

P = 2.835 Watts

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3 years ago
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Which types of electromagnetic waves have wavelengths that are longer than those of visible light but shorter than those of micr
grin007 [14]

Answer:

On one end of the electromagnetic spectrum are radio waves, which have wavelengths billions of times longer than those of visible light. On the other end of the spectrum are gamma rays, with wavelengths billions of times smaller than those of visible light.

Explanation:

add me as brainliest if u the answer is helpful

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3 years ago
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Which formula can be used to find the magnitude of the resultant vector? R2 = Rx2 + Ry2 R = Rx + Ry R = Rx(cosθ) R = Rx(sinθ)
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R^2 = rx^2 + ry^2 !!!!!!!!!!
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3 years ago
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A sled is moving at a constant speed down a surface inclined at 45.0° with the horizontal and travels 30 meters in 4 seconds. Ca
slamgirl [31]
To obtain the vertical component of the velocity, it is necessary to multiply the velocity at this time by sin 45 degrees. Since the velocity is not given, it must be solved first by dividing the distance by the time. To show this:

Velocity = distance / time
Velocity = 30 m / 4s
Velocity = 7.5 m/s

Vertical velocity = 7.5 sin 45
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5 0
3 years ago
A 12.0-g sample of carbon from living matter decays at the rate of 162.5 decays/minute due to the radioactive 14C in it. What wi
Ghella [55]

Answer:

a)143.8 decays/minute

b)0.41 decays/minute

Explanation:

From;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2=half-life of C-14= 5670 years

t= time taken to decay

Ao= activity of a living sample

A= activity of the sample under study

a)

0.693/5670 = 2.303/1000 log(162.5/A)

1.22×10^-4 = 2.303×10^-3 log(162.5/A)

1.22×10^-4/2.303×10^-3 = log(162.5/A)

0.53 × 10^-1 = log(162.5/A)

5.3 × 10^-2 = log(162.5/A)

162.5/A = Antilog (5.3 × 10^-2 )

A= 162.5/1.13

A= 143.8 decays/minute

b)

0.693/5670 = 2.303/50000 log(162.5/A)

1.22×10^-4 = 4.61×10^-5 log(162.5/A)

1.22×10^-4/4.61×10^-5 = log(162.5/A)

0.26 × 10^1 = log(162.5/A)

2.6= log(162.5/A)

162.5/A = Antilog (2.6 )

A= 162.5/398.1

A= 0.41 decays/minute

4 0
3 years ago
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