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photoshop1234 [79]
3 years ago
6

5+15 divided by 3 x 4 to the third power

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0

Answer:

325

Step-by-step explanation:

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Solve By Factoring: 7x^2+6x-3=0
Allushta [10]

Answer:

x= -3-sqr30/7

Step-by-step explanation:

3 0
3 years ago
Evaluate each of the following. help plz
Mariulka [41]

Answer:

5!= 120

13!= 6227020800

12!/6!= 665280

10!/7! 3!= 120

5(4!)= 120

Step-by-step explanation:

7 0
3 years ago
Given a mean of 52.3 and a standard deviation of 1.8, what is the z-score of the value 51.8 rounded to the nearest tenth?
postnew [5]
The z-score of a certain data point in the given statistical data is calculated through the equation,
                                           z-score = (x - m) / sd
where x is the data point, m is the mean and sd is the standard deviation. 
Substituting the known values,
                                           z-score = (51.8 - 52.3) / 1.8
                                           z-score = -0.277
Rounding the answer to the nearest tenth will give an answer of -0.3. 
8 0
3 years ago
A company has two packaging machines in a unit, each with a different daily capacity. The capacity of machine 1 is defined by th
ollegr [7]

Total capacity = sum of the individual production capacities.

Here,

Total capacity = sum of f(m) = (m + 4)^2 + 100  and g(m) = (m + 12)^2 − 50.

Then f(m) + g(m) =  (m + 4)^2 + 100 + (m + 12)^2 − 50.

We must expand the binomial squares in order to combine like terms:

 m^2 + 8 m + 16 + 100

+m^2 + 24m + 144 - 50

---------------------------------

Then f(m) + g(m) = 2m^2 + 32m + 160 + 50  

      f(m) + g(m)   = 2m^2 + 32m + 210, where m is the number of

                                minutes during which the two machines operate.

6 0
3 years ago
The ratio of girls to boys competing at a gymnastics competition was 2 to 1 there were 75 kids participating in the competition.
skad [1K]

Answer:

  25 boys

Step-by-step explanation:

1 of 3 kids was a boy, so (1/3)·75 = 25 were boys.

8 0
3 years ago
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