This is what is normally termed a single replacement reaction, although don't hold me to that. It could have changed to something more modern.
Answer:
306.43 K
Explanation:
- Use Charle's law and rearrange formula (V1/T1=V2/T2)
- Hope this helped! Let me know if you would like me to show you step-by-step how to do these types of problems.
Answer:
E = 3.9 x 10⁻²⁰ J
Explanation:
<u>Step 1:</u>
Before you can find the energy of the light, you need to find the wavelength. To find the wavelength, you need to use two equations:
w = c / f
In this formula, "w" is the wavelength (m), "c" is the speed of light (m/s), and "f" is the frequency. "C" is a constant with the value 3.0 x 10⁸ m/s. Since you have been given frequency and the constant, you can plug these values into the equation and solve for wavelength.
w = c / f
w = (3.0 x 10⁸ m/s) / (5.9 x 10¹³ sec⁻¹)
w = 5.1 x 10⁻⁶ m
<u>Step 2:</u>
To find the energy, you need to use the following equation:
E = hc / w
In this formula, "E" is the energy (J), "h" is Planck's constant (J/s), and "c" and "w" are the same as above. "H" is a constant with the value 6.626 x 10⁻³⁴ J/s. Since you found the wavelength and have been given the constants, you can plug them into the equation and find energy.
E = hc / w
E = (6.626 x 10⁻³⁴ J/s)(3.0 x 10⁸ m/s) / (5.1 x 10⁻⁶ m)
E = (1.99 x 10⁻²⁵) / (5.1 x 10⁻⁶ m)
E = 3.9 x 10⁻²⁰ J
I think it's - log [H3O^+]
P.S. the 3 is a lowered exponent
