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serg [7]
3 years ago
7

Can a particle with constant speed be accelarating?what if it has constant velocity?​

Physics
1 answer:
Olin [163]3 years ago
7 0

Explanation:

it can be safely concluded that an object moving in a circle at constant speed is indeed accelerating. It is accelerating because the direction of the velocity vector is changing.

When an object is moving with constant velocity, it does not change direction nor speed and therefore is represented as a straight line when graphed as distance over time.

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Suppose someone pours 0.250 kg of 20.0ºC water (about a cup) into a 0.500-kg aluminum pan with a temperature of 150ºC. Assume th
Troyanec [42]

Answer : The temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of aluminium = 0.90J/g^oC

c_2 = specific heat of water = 4.184J/g^oC

m_1 = mass of aluminum = 0.500 kg = 500 g

m_2 = mass of water = 0.250 kg  = 250 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of aluminum = 150^oC

T_2 = initial temperature of water = 20^oC

Now put all the given values in the above formula, we get:

500g\times 0.90J/g^oC\times (T_f-150)^oC=-250g\times 4.184J/g^oC\times (T_f-20)^oC

T_f=59.10^oC

Therefore, the temperature when the water and pan reach thermal equilibrium short time later is, 59.10^oC

8 0
3 years ago
half life worksheet answer key 3. What percent of a sample As-81 remains un-decayed after 43.2 seconds
Ivahew [28]

The final mass after decay can be obtained by using under given relation:

half life period of As-81 = 33 seconds

mf = mi x (1/2^n)

= 100 x ( 1/2^(43.2/33))

= 40.4 %


3 0
3 years ago
2 a A pile of 60 sheets of paper is 6 mm high. Calculate the average thickness of a sheet of the paper.
fiasKO [112]

The average thickness of a sheet of the paper is 0.1 mm.

The number of ice blocks that can be stored in the freezer is 80 blocks of ice.

<h3>Average thickness of a sheet of the paper</h3>

The average thickness of a sheet of the paper is calculated as follows;

average thickness = 6 mm/60 sheets = 0.1 mm /sheet

Thus, the average thickness of a sheet of the paper is 0.1 mm.

<h3>Volume of each block of ice</h3>

Volume = 10 cm x 10 cm x 4 cm

Volume = 400 cm³

<h3>Volume of the freezer</h3>

Volume = 40 cm x 40 cm x 20 cm = 32,000 cm³

<h3>Number of ice blocks that can be stored</h3>

n = 32,000 cm³/400 cm³

n = 80 blocks of ice

Thus, the number of ice blocks that can be stored in the freezer is 80 blocks of ice.

Learn more about average thickness here: brainly.com/question/24268651

#SPJ1

6 0
1 year ago
A table is moved using 60 N of force.
dem82 [27]

Answer:

15m

Explanation:

W=f×s

s =  \frac{w}{f} \\ s =  \frac{900j}{60n} \\ s = 15m

5 0
2 years ago
Two cylindrical resistors are made of the same material and have the same resistance. The resistors, R1 and R2, have different r
Paladinen [302]

Answer:

Option d is correct.

Explanation:

We know , resistance of a body is directly proportional to its length and inversely proportional to its area.

R=\dfrac{\rho\ L}{A}=\dfrac{\rho\ L}{\pi r^2}      ( Here, \rho is constant dependent on object material )

Writing R_1 \ and\ R_2 also :

R_1=\dfrac{\rho\ L_1}{\pi r_1^2}\ , \  R_2=\dfrac{\rho\ L_2}{\pi r_2^2}      ( since they are of same material therefore, \rho is same.)

Now , if r_2=2r_1 \ and \ 4L_1=L_2.

Then R_1=R_2

Therefore, option d. is correct.

Hence, this is the required solution.

7 0
3 years ago
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