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jasenka [17]
3 years ago
7

Brainly app · Installed

Physics
1 answer:
Sauron [17]3 years ago
6 0
I need a picture plz I don’t know what to answer.
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Eats plants and meats
VMariaS [17]
Omnivores e<span>at both plants and meats. </span>
8 0
3 years ago
Read 2 more answers
Which is not true of the Intertropical Convergence Zone?A) It features heavy precipitation B) It's where the trade winds collide
olasank [31]
<h2>Answer: C) It's a high-pressure zone with sinking air</h2>

Explanation:

The intertropical convergence zone is the region of the terrestrial globe where the trade winds of the northern hemisphere converge with those of the southern hemisphere.  

It is characterized by being <u>a belt of low pressure</u> and inconsistent location around the equator constituted by ascending air currents, where large masses of warm and humid air converge from the north and south of the intertropical zone.  

The reason of its inconsistent location is due to the movements of the Earth with the seasons, having as a consequence the amount variation of heat energy from the sun in this region.

7 0
3 years ago
Which statement about the sun's energy is correct?
Vera_Pavlovna [14]
I believe it’s A. I know for sure it isn’t D.
6 0
3 years ago
A 0.500-nm x-ray photon is deected through 134 in a Compton scattering event. At what angle (with respect to the incident beam)
natita [175]

Answer:

The angle of recoil electron with respect to incident beam of photon is 22.90°.

Explanation:

Compton Scattering is the process of scattering of X-rays by a charge particle like electron.

The angle of the recoiling electron with respect to the incident beam is determine by the relation :

\cot\phi = (1+\frac{hf}{m_{e}c^{2}  })\tan\frac{\theta }{2}      ....(1)

Here ∅ is angle of recoil electron, θ is the scattered angle, h is Planck's constant, m_{e} is mass of electron, c is speed of light and f is the frequency of the x-ray photon.

We know that, f = c/λ      ......(2)

Here λ is wavelength of x-ray photon.

Rearrange equation (1) with the help of equation (1) in terms of  λ .

\cot\phi = (1+\frac{h}{m_{e}c\lambda  })\tan\frac{\theta }{2}

Substitute 6.6 x 10⁻³⁴ m² kg s⁻¹ for h, 9.1 x 10⁻³¹ kg for m_{e}, 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ  and 134° for θ in the above equation.

\cot\phi = (1+\frac{6.6\times10^{-34} }{9.1\times10^{-31}\times3\times10^{8}\times0.5\times10^{-9}  })\tan\frac{134 }{2}

\cot\phi=2.37

\phi = 22.90°

8 0
3 years ago
Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. The electric field at a po
gregori [183]

Answer:

E = 0    r <R₁

Explanation:

If we use Gauss's law

      Ф = ∫ E. dA = q_{int} / ε₀

in this case the charge is distributed throughout the spherical shell and as we are asked for the field for a radius smaller than the radius of the spherical shell, therefore, THERE ARE NO CHARGES INSIDE this surface.

Consequently by Gauss's law the electric field is ZERO

           E = 0    r <R₁

6 0
3 years ago
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