Answer:
7 m/s
Explanation:
Acceleration,
Where v and u are the final and initial velocities of the Justine respectively, t is the time taken for Justin to attain final velocity.
Making v the subject then
v=at+u
Taking u as zero then
Substituting 3.5 for t, 2 as a then
v=3.5*2=7 m/s
Answer:the mass Of The object,and there area Of The bottom surface
Explanation:
There mass Of The object, and the area Of The bottom surface
Answer:
A) A circle starting at time t=0 on the positive x axis
.
B) .
C) v(t)=Rω[-sin(ωt)i^+cos(ωt)j^]
D) v(t)=Rω
E) a(t)=-R[cos(ωt)i^+sin(ωt)j^]
F) a(t)=-r(t)
G) (There is no Part G)
H) a=/R
Explanation:
The particle's motion is a circle starting at t=0 on the positive x axis since r(0)=R[cos(0)i^+sin(0)j^]=R[i^]. The particle first cross the negative x axis when r(t)=-R[i^], which means cos(ωt)=-1, or , so we have . The particle's velocity is the derivative of its position, so v(t)=Rω[-sin(ωt)i^+cos(ωt)j^], while its speed is the magnitude of that vector, v(t)=Rω (since the magnitude of the vector -sin(ωt)i^+cos(ωt)j^ is 1). The particle's acceleration is the derivative of its velocity, so a(t)=-R[cos(ωt)i^+sin(ωt)j^], or in terms of its position a(t)=-r(t), and its magnitude using the expression obtained for the speed of the particle, a=R=R/=/R.
Answer:
The wavelength of the light is .
Explanation:
Given that,
Distance between the slit centers d= 1.2 mm
Distance between constructive fringes
Distance between fringe and screen D= 5 m
We need to calculate the wavelength
Using formula of width
Put the value into the formula
Hence, The wavelength of the light is .
To solve this problem it is necessary to consider two concepts. The first of these is the flow rate that can be defined as the volumetric quantity that a channel travels in a given time. The flow rate can also be calculated from the Area and speed, that is,
Q = V*A
Where,
A= Cross-sectional Area
V = Velocity
The second concept related to the calculation of this problem is continuity, which is defined as the proportion that exists between the input channel and the output channel. It is understood as well as the geometric section of entry and exit, defined as,
Our values are given as,
Re-arrange the equation to find the first ratio of rates we have:
The second ratio of rates is