1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
igomit [66]
3 years ago
13

A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this time, the train moves a

distance of meters.
Physics
2 answers:
jeka57 [31]3 years ago
7 0

So lets fill out what we have first:

Vi or initial velocity = 20 m/s

Acceleration or a = 4 m/s^2

Time for the motion = 10s

Now, using the four main kinematic equations we can deduce that the best kinematic equation to use in these terms is:

Δx = Vi(t) + 0.5at²

Plug all of our information in:

Δx = (20)(10) + (0.5)(4)(100)

Δx = 400 m

alekssr [168]3 years ago
7 0

Answer:

400 m

Explanation:

answer on ed

You might be interested in
Why do waves with frequencies higher than visible light hurt while those with lower frequencies do not affect us?
STALIN [3.7K]
Lower frequency waves have less strength to penetrate. How bad a wave is all depends on how well it penetrates our bodies. Visible light doesn't penetrate ur skin, but UV rays (higher than visible) can go through our skin, making it <span>bad" for us. High frequency waves have more energy and move faster</span>
7 0
3 years ago
Read 2 more answers
(Figure 1) shows the angular-velocity-versus-time graph for a particle moving in a circle. How many revolutions does the object
Travka [436]

Answer: 10.34

Explanation:

Given

\omega -t graph for a particle is given

angle turned by the particle in radians is given by the area under \omega -t graph

The area is given by

A=20\times (2-0)+10(4-2)+\dfrac{1}{2}\times (20-10)\times (3-2)\\A=40+20+5=65\ rad

Revolutions(N) made by the object is given by

N=\dfrac{65}{2\pi }=10.34

4 0
3 years ago
What is in the boron family with 3 valence electrons
olganol [36]
Boron, Aluminum, Gallium, Indium, Thallium
7 0
3 years ago
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 78.5 m/s. Th
Andrews [41]

Answer:

FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

Explanation:

First you have to consider that the Ford Thunderbird (FT) follows a rectilinear motion with varying acceleration, while Mercedez Benz (MB) has a constant velocity (no acceleration). So if you finde the time spent by FT in each section, and the distance, then you will find the distance for MB.

1) Vf² = Vi² + 2ad, where Vf: final velocity, Vi: ionitial velocity, a: acceleration and d: distance.

For the first portion  (0 m/s)² = (78.5 m/s)² + 2a(250 m) ⇒

-(78.5 m/s)² / 2(250m) = a ⇒ a = -12.3 m/s².

Now, you can find the corresponding time for this section with the following formule: Vf = Vi + at ⇒ 0 m/s = 78.5 m/s + (-12.3 m/s²) t

⇒ t= (-78.5 m/s)/ (-12.3 m/s²) ⇒ t= 6.4 seconds.

2) Then FT spent 5 seconds in the pit.

3) The the FT accelerates until reach 78.5 m/s again in a distance of 370 m.

Vf² = Vi² + 2ad ⇒ (78.5 m/s)² = (0 m/s)² + 2a(370 m)

⇒ (78.5 m/s)²/ 2(370 m) = a ⇒ a = 8.3 m/s²

Then, Vf = Vi + at ⇒ 78.5 m/s = 0 m/2 + (8.3 m/s²) t

⇒ (78.5 m/s)/(8.3 m/s²) = t ⇒ t = 9.5 seconds.

4) Summarizing, the FT moves 620 meters (250 + 370 mts) in 20.9 seconds ( 6.4 s + 5 s + 9.5 s).

5) During this time, MB moves

Velocity = distance/ time ⇒ Velocity x time = Distance

⇒ Distance = (78.5 m/s) x  (20.9 seconds) ⇒ Distance = 1640.6 meters

6) Finally, the FT is 1020.6 meters (1640.6 meters - 620 meters) far from MB

3 0
3 years ago
At a meeting of physics teacher in Montana, the teachers were asked to calculate where a flour sack would land if dropped from a
Harlamova29_29 [7]

At a distance of 469.2 m from the original point below the airplane.

Explanation:

First of all, we have to calculate the time it takes for the sack to reach the ground.

To do so, we just analyze its vertical motion, which is a free-fall motion, so we can use the suvat equation:

s=ut+\frac{1}{2}at^2

where, taking downward as positive direction:

s = 300 m is the vertical displacement

u = 0 is the initial vertical velocity

t is the time

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for t, we find the it takes for the sack to reach the ground:

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(300)}{9.8}}=7.82 s

Now we analyze the horizontal motion. The horizontal velocity of the pack is constant (since there are no forces along the horizontal direction) and equal to the initial speed of the airplane, so:

v_x = 60 m/s

We also know the total time of flight,

t = 7.82 s

Therefore, we can find the horizontal distance travelled by the sack:

d=v_x t = (60)(7.82)=469.2 m

So, the sack will land 469.2 m from the original point below the airplane.

Learn more about free fall and projectile motion:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

brainly.com/question/8751410

#LearnwithBrainly

7 0
3 years ago
Other questions:
  • A +4.0- μC charge is placed on the x axis at x = +3.0 m, and a −2.0- μC charge is located on the y axis at y = −1.0 m. Point A i
    9·1 answer
  • Explain why streets and highways have speed limits and not velocity limits.
    6·1 answer
  • A bicyclist was moving at a rate of 8 m/s, and then sped up to 10 m/s. If the cyclist has a mass of 120 kg, how much work was ne
    11·2 answers
  • I have two questions I need help with.
    8·1 answer
  • A car traveling at 45 km/h starts to brake, and comes to a stop over a distance of 18 m. Calculate the acceleration
    12·1 answer
  • “I am sure I will get a good grade on this project. I’ve worked really hard; my teacher will recognize my efforts!” This stateme
    5·2 answers
  • What unbalanced force is needed to give a 976 kg vehicle an acceleration of 2.50 m/s2? ASAP
    11·1 answer
  • Topic: Chapter 19: Some wiggle room
    8·1 answer
  • An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object
    13·1 answer
  • Helppppppp its exam ​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!