<span>C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.
Let's look at the available choices and determine why or why not they're correct.
A) Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles.
* What? So increasing the pressure on a gas will make it take up a larger volume? That definitely doesn't match the world I live in. I hope that's true for you as well. Wrong choice.
B) Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.
* Lots of interesting sounding words, but they're mostly used in a nonsense fashion. Useful if you're easily fooled by technobabble, but it's another wrong answer.
C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.
* OK. Increasing the pressure will compress a gas. So it has a smaller volume. And since it still has the same mass, the density will become greater. And the particles closer together. Everything here matches reality. Good choice.
D) Pressure will accelerate a gas, extending its volume and allowing a smaller density and concentration of particles.
* Most technobabble. Why would the gas be accelerated? No reason that I know of. Wrong choice.</span>
Answer:
625 piece.
Explanation:
Let n be the required no of piece
200 litre = 200 x 10⁻³ m³ = 200 x 10⁻³ x 10³ kg = 200 Kg
mass of ice piece = n x 30 x /1000
Heat lost by ice pieces = (n x 30) / 1000 x ( 80 + 1 x 16⁰C)
Heat gained by water = 200 x 1 x 9⁰C
Heat lost = Heat gained
(n x 30) /1000 x ( 80 + 16 ) =200 x 9
2.88 n = 1800
n = 625
Answer:
Femur
Explanation:
The femur is the single bone of the thigh region. It articulates superiorly with the hip bone at the hip joint, and inferiorly with the tibia at the knee joint.
Answer:
The answer to your question is given below
Explanation:
Since both object A and B were dropped from the same height and the air resistance is negligible, both object A and B will get to the ground at the same time.
From the question, we were told that object A falls through a distance to dA at time t and object B falls through a distance of dB at time 2t.
Remember, both objects must get to the ground at the same time..!
Let the time taken for both objects to get to the ground be t.
Time A = Time B = t
But B falls through time 2t
Therefore,
Time A = Time B = 2t
Height = 1/2gt^2
For A:
Time = 2t
dA = 1/2 x g x (2t)^2
dA = 1/2g x 4t^2
For B
Time = t
dB = 1/2 x g x t^2
Equating dA and dB
dA = dB
1/2g x 4t^2 = 1/2 x g x t^2
Cancel out 1/2, g and t^2
4 = 1
4dA = dB
Divide both side by 4
dA = 1/4 dB