All categories

3 years ago

How many inches tall is a 7 foot basket ball player

Mathematics

2 answers:

andrey2020 [161]3 years ago

6 0

7 inches obviously thanks for the points

forsale [732]3 years ago

3 0

Answer:

84 in

Step-by-step explanation:

my head

You might be interested in

Let ∠1, ∠2, and ∠3 have the following relationships.

Kaylis [27]

Answer:

sry im being Dumb im pretty sure its 180 because intersecting lines form vertical angles if those angles are acute the one in between is obtuve a like is 180 degrees

7 0

3 years ago

Find the slope of the line. A. -1/3 B. 1/3 C. 3 D. -3

denis23 [38]

The answer is C! :)

8 0

3 years ago

Read 2 more answers

Farmer McKinney has a plot of tomato plants. There are 5 tomato plants in the first row, 6 tomato plants in the second row, 9 to

jok3333 [9.3K]

There will be 30 tomatoes in row six. Let me know if i'm right.

3 0

3 years ago

Name two segments the represent radii.be sure to write the word segment and then use two letters to identify the radii

SCORPION-xisa [38]

Answer:

Step-by-step explanation:

3 0

3 years ago

The probability density function of the time you arrive at a terminal (in minutes after 8:00 A.M.) is f(x) = 0.1 exp(−0.1x) for

Blababa [14]

$f_X(x)=\begin{cases}0.1e^{-0.1x}&\text{for }x>0\\0&\text{otherwise}\end{cases}$

a. 9:00 AM is the 60 minute mark:

$f_X(60)=0.1e^{-0.1\cdot60}\approx0.000248$

b. 8:15 and 8:30 AM are the 15 and 30 minute marks, respectively. The probability of arriving at some point between them is

$\displaystyle\int_{15}^{30}f_X(x)\,\mathrm dx\approx0.173$

c. The probability of arriving on any given day before 8:40 AM (the 40 minute mark) is

$\displaystyle\int_0^{40}f_X(x)\,\mathrm dx\approx0.982$

The probability of doing so for at least 2 of 5 days is

$\displaystyle\sum_{n=2}^5\binom5n(0.982)^n(1-0.982)^{5-n}\approx1$

i.e. you're virtually guaranteed to arrive within the first 40 minutes at least twice.

d. Integrate the PDF to obtain the CDF:

$F_X(x)=\displaystyle\int_{-\infty}^xf_X(t)\,\mathrm dt=\begin{cases}0&\text{for }x$

Then the desired probability is

$F_X(30)-F_X(15)\approx0.950-0.777=0.173$

7 0

3 years ago