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3 years ago

Please help meeee its for physics....

Physics

1 answer:

vekshin13 years ago

8 0

Nothing accelerates a Projectile Horizontally during Motion...

Consequently

Horizontal Acceleration is Always Zero.

The Horizontal Velocity is always Constant too.

Only the vertical Velocity changes by -9.8ms-².

If this is so...

∆x = v'∆t + ½(0)(∆t)²

∆x = v't.

I'd go with Option D.

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A 50.0-kg girl stands on a 9.0-kg wagon holding two 13.5-kg weights. She throws the weights horizontally off the back of the wag

Kobotan [32]

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5 0

3 years ago

How long does it take light to travel 850 km in a vacuum? Answer in ms.(Express your answer to two significant figures.)

poizon [28]

Answer:

0.002833 sec

Explanation:

Speed of light in vacuum is $3\times 10^{8}m/sec$

Given distance = 850 km = 850×1000=850000 m

We have to calculate the time that light take to travel the distance 850 km

Time $T=\frac{distance }{speed}=\frac{850000}{3\times 10^8}=2.833\times 10^{-3}sec$

So the time taken by light to travel 850 km is 0.002833 sec

5 0

3 years ago

You and your friend are going bungee jumping! You wait directly below them with a camera. When they leap from the bridge they be

Alex

Answer:

The amplitude is $A = 90.2 \ m$

Explanation:

From the question we are told that

The frequency of when sound is approaching observer is $f = 392 Hz$

The frequency as the move away from observer is $f_ a = 330 \ Hz$

The time between the pitch are $t = 10 \ s$

Here you are the observer and your friends are the source of the sound

The period is mathematically evaluated as

$T = 2 t$

as it is the time to complete one oscillation which from on highest pitch to the next highest pitch

Now T can also be mathematically represented as

$T = \frac{2 \pi}{w}$

Where $w$ is the angular velocity

=> $\frac{2 \pi}{w} = 2 * 10$

=> $w = 0.314 \ rad/sec$

Now using Doppler Effect,

The source of the sound is approaching the observer

The

$f = f_o (\frac{v}{v- wA} )$

$392 = f_o (\frac{v}{v- wA} )$

Where A is the amplitude

So when the source is moving away from the observer

$f_a = f_o (\frac{v}{v+ wA} )$

$330 = f_o (\frac{v}{v+ wA} )$

Here $f_o$ is the fundamental frequency

Dividing the both equation we have

$\frac{392}{330} = \frac{f_o(\frac{v}{v-wA} )}{f_o(\frac{v}{v+wA}}$

$1.1878 = \frac{v+wA}{v-wA}$

$1.1878 v - 1.1878 wA = v+wA$

$1.1878 v = 2.1878 wA$

=> $A = \frac{(0.1878 * (330))}{(2.1878)* (0.314)}$

$A = 90.2 \ m$

7 0

3 years ago

which of the following statements best justifies the inclusion of test tube v as a control in the experiment? responses it will

prohojiy [21]

The following statement which best justifies the inclusion of test tube v as a control in the experiment is that it will show the color change that occurs in the absence of enzyme activity and is denoted as option C.

<h3>What is an Enzyme?</h3>

This is referred to as a biological catalyst which is involved in the speeding up of the rate of a reaction by lowering the activation energy used to initiate the reaction.

Enzymes are known as proteinous in nature and are denatured by heat and other substances is included in the test tube v as a control in the experiment is that it will show the color change that occurs in the absence of enzyme activity.

This therefore helps to differentiate the enzymatic processes which takes place in a substance or body therefore making option C the correct choice.

Read more about Enzyme here brainly.com/question/1596855

#SPJ1

The options are:

It will provide a measurement of amylase activity at an acidic pH.
it will provide a measurement of amylase activity at a basic pH.
It will show the color change that occurs in the absence of enzyme activity.
it will show the color change that occurs in the absence of the amylase protein.

It will show the color change that occurs in the absence of enzyme activity.

5 0

1 year ago

A car movingin a straight line starts at x = 0 at t = 0. It passes the point x = 25.0 m with a speed of 11.0 m????s at t = 3.00s

makvit [3.9K]

Answer:

Part a)

at t = 3.00 s

$v = 8.33 m/s$