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3 years ago

Please help meeee its for physics....

Physics

1 answer:

vekshin13 years ago

8 0

Nothing accelerates a Projectile Horizontally during Motion...

Consequently

Horizontal Acceleration is Always Zero.

The Horizontal Velocity is always Constant too.

Only the vertical Velocity changes by -9.8ms-².

If this is so...

∆x = v'∆t + ½(0)(∆t)²

∆x = v't.

I'd go with Option D.

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xxTIMURxx [149]

Answer:

I think d or b maybe it's d

3 0

3 years ago

Q:1 write down the differences between mass and weight ?

Evgesh-ka [11]

Answer:

mass is the amount of "matter" in an object. weight is the force exerted on an object by gravity

Explanation:

7 0

3 years ago

Two people push on a boulder to try to move it. The mass of the boulder is 815 kg. One person pushes north with a force of 65 N.

ivanzaharov [21]

Answer:

$0.095 m/s^2$

Explanation:

As the 2 force directions are perpendicular (North vs West), we can calculate the magnitude of the net force using the following equation

$F = \sqrt{65^2 + 42^2} = 77.4 N$

Assuming negligible friction, from here we can calculate the acceleration in accordance to Newton's 2nd law of motion

$a = F/m = 77.4 / 815 = 0.095 m/s^2$

3 0

3 years ago

a sample of ideal gas is originally at 40 degrees celsius. what is the final temperature of the gas if the volume is doubled and

Assoli18 [71]

Answer:

313 K or 40 degree celsius.

Explanation:

Initial , $V_{i}=V_{0}$

$P_{i}=P_{0}$

$T_{i} =40+273=313K$

Now, final

$P_{f} =\frac{1}{2}P_{0}$

$V_{f} =2V_{0}$

Combined the ideal gas law

$\frac{P_{i}V_{i}}{T_{i}}=\frac{P_{f}V_{f}}{T_{f}} \\\frac{P_{0}V_{0}}{T_{0}}=\frac{1}{2} \frac{P_{0}2V_{0}}{T_{f}} \\T_{f}=T_{0}\\T_{f}=313K$

Therefore, the final temperature of ideal gas is 313 K.

4 0

4 years ago

A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle

aalyn [17]

Answer:

4.56 s

Explanation:

Let t (seconds) be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. Since prior to this they are traveling at constant speed, they would have maintained a distance of 52 m before accelerating.

The distance traveled by the car, with respect the motorcycle position when it start accelerating is

$s_c = s_0 + v_ct = 52 + 19t$