You are holding a block of wood with dimensions 3 cm 6 cm 9 cm on the palm of your hand. Which side must be touching your hand f
2 answers:
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Given that,
Mass of object = 9.90 kg
Time =5.40 s
Suppose the force is (2.00i + 9.00j + 5.30k) N, initial position is (2.70i - 2.90j + 5.50k) m and final position is (-4.10i + 3.30j + 5.40k) m.
We need to calculate the displacement
Using formula of displacement
Where, = initial position
= final position
Put the value into the formula
(a). We need to calculate the work done on the object
Using formula of work done
Put the value into the formula
(b). We need to calculate the average power due to the force during that interval
Using formula of power
Where, P = power
W = work
t = time
Put the value into the formula
(c). We need to calculate the angle between vectors
Using formula of angle
Put the value into the formula
Hence, (a). The work done on the object by the force in the 5.40 s interval is 41.67 J.
(b). The average power due to the force during that interval is 7.71 Watt.
(c). The angle between vectors is 79.7°