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vekshin1
3 years ago
9

A gas sample at 83 °C occupies a volume of

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

1800

Explanation:

because u have to do the mulipication

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11. You have 700 grams of AgO. How many moles are present?
solniwko [45]
<h2>Answer:</h2>

5.65moles

<h2>Explanations:</h2>

The formula for calculating the number of moles the compound contain is given as:

moles=\frac{Mass}{Molar\text{ mass}}

Given the following parameters

Mass of Ag = 700grams

Determine the molar mass of AgO

Molar mass = 107.87 + 16

Molar mass = 123.87g/mol

Determine the moles of AgO

\begin{gathered} moles=\frac{700}{123.87} \\ moles\text{ of AgO}=5.65moles \end{gathered}

Hence the moles of AgO present is 5.65moles

7 0
1 year ago
Calculate the pHpH of a 0.10 MM solution of HClHCl . Express your answer numerically using two decimal places.
alisha [4.7K]

Answer: The pH 0f 0.10 solution of HCl is 1.00

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

HCl\rightarrow H^++Cl^{-}

According to stoichiometry,  

1 mole of HCl gives 1 mole of H^+  

Thus 0.10 moles of HCl gives =\frac{1}{1}\times 0.10=0.10 moles of H^+  

Putting in the values:

pH=-\log[0.10]

pH=1.00

Thus pH 0f 0.10 solution of HCl is 1.00

8 0
2 years ago
Lonic or Covalent? Fe2O3
yan [13]
Fe2o3 this is covalent
8 0
2 years ago
How many calories of heat are necessary to raise the temperature of 319.5 g of water from 35.7 °C
rjkz [21]

20600Cal              

Explanation:

Given parameters:

Mass of water = 319.5g

Initial temperature = 35.7°C

Final temperature = 100°C

Unknown:

Calories needed to heat the water = ?

Solution:

The calories is the amount of heat added to the water. This can be determined using;

     H  =   m  c Ф

c  = specific heat capacity of water = 4.186J/g°C

   H is the amount of heat

    Ф is the change in temperature

    H = m c (Ф₂ - Ф₁)

    H = 319.5 x 4.186 x (100 - 35.7) = 85996.56J

Now;

     1kilocalorie = 4184J

     

85996.56J to kCal; \frac{85996.56}{4184}   = 20.6kCal  = 20600Cal

               

learn more:

Specific heat brainly.com/question/3032746

#learnwithBrainly

6 0
3 years ago
The hydrogens and oxygen of a water molecule are held together by ______ bonds.
umka2103 [35]
The hydrogens and oxygen of a water molecule are held together by covalent bond
6 0
3 years ago
Read 2 more answers
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