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3 years ago

I'LL MARK BRAINLIEST

Physics

1 answer:

masya89 [10]3 years ago

3 0

Answer:

B law of conversation of energy

Explanation:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside.

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Each water molecule is joined to _____ other water molecules by ____ bonds.

levacccp [35]

Answer:

D) four ... hydrogen

Explanation:

8 0

3 years ago

Read 2 more answers

The diagram shows vectors that are not perpendicular to one another.

Artist 52 [7]

The angle of the resultant vector, rounded to the nearest tenth is determined as 36.9⁰.

<h3>Magnitude of components vectors</h3>

The resultant vector of the three vectors can be determined from the magnitude of the components vectors.

Ex = 2

Fx = 4

Gx = 2

Ey = 2

Fy = 1

Gy = 3

∑Vx = Ex + Fx + Gx = 2 + 4 + 2 = 8

∑Vy = Ey + Fy + Gy = 2 + 1 + 3 = 6

<h3>Angle of the resultant vector</h3>

tanθ = Vy/Vx

tanθ = 6/8

tanθ = 0.75

θ = tan⁻¹(0.75)

θ = 36.9⁰

Thus, the angle of the resultant vector, rounded to the nearest tenth is determined as 36.9⁰.

Learn more about resultant vector here: brainly.com/question/110151

#SPJ1

8 0

2 years ago

The temperature of a sample of silver increased by 24.0 °C when 269 J of heat was applied. What is the mass of the sample?

statuscvo [17]

Answer:

Mass of the silver will be equal to 46.70 gram

Explanation:

We have given heat required to raise the temperature of silver by 24°C is 269 J , so $\Delta T=24^{\circ}C$

Specific heat of silver = 0.240 J/gram°C

We have to find the mass of silver

We know that heat required is given by

$Q=mc\Delta T$ , here m is mass, c is specific heat of silver and $\Delta T$ is rise in temperature

So $269=m\times 0.240\times 24$

m = 46.70 gram

So mass of the silver will be equal to 46.70 gram

3 0

3 years ago

A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The linear speed of a passenger on the

Marina86 [1]

Answer:

a) The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 90^{\circ}$ .

b) Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 270^{\circ}$ .

c) The Ferris wheel takes 14.646 seconds to make a revolution.

Explanation:

a) An object that rotates at constant angular velocity reports a centripetal acceleration and no tangential acceleration. When passenger passes through the lowest point in her circular motion, centripetal acceleration goes up to the center.

In addition, centripetal acceleration is determined by the following expression:

$a_{R} = \frac{v^{2}}{R}$ (Eq. 1)

Where:

$a_{R}$ - Centripetal acceleration, measured in meters per square second.

$v$ - Linear speed, measured in meters per second.

$R$ - Radius of the Ferris wheel, measured in meters.

If we know that $v = 6\,\frac{m}{s}$ and $R = 14\,m$ , the magnitude of radial acceleration is:

$a_{R} = \frac{\left(6\,\frac{m}{s} \right)^{2}}{14\,m}$

$a_{R} = 2.571\,\frac{m}{s^{2}}$

The acceleration experimented by the passenger when she passes through the lowest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 90^{\circ}$ .

b) In the highest point the magnitude of radial acceleration is the same but direction is the opposed to that at lowest point. That is, centripetal acceleration goes down to the center.

Hence, the acceleration experimented by the passenger when she passes through the highest point of her circular motion is: $a_{R} = 2.571\,\frac{m}{s^{2}}$ , $\angle = 270^{\circ}$ .

c) At first we need to calculate the angular velocity of the Ferris wheel ( $\omega$ ), measured in radians per second, by using the following expression: