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Leto [7]
3 years ago
10

How do you solve the following equation for x? −2x²−8x+24=0

Mathematics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

−2x²−8x+24=0

4x - 8x + 24 = 0

- 4x + 24 = 0

-4x = 24

x = -6

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the ratio of blue to marbles to red marbles in a box is 2 to 1 . If there are 12 blue marbles in the box then how many blue &amp
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❖ There are a total of 18 marbles.

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3 years ago
Solve the equation : <br><img src="https://tex.z-dn.net/?f=%20%5Ccos%28x%29%20-%20%20%5Csin%28x%29%20%20%3D%20%20%5Csqrt%7B2%20%
Debora [2.8K]

Answer:

General solution is

 x = n \pi + \frac{\pi }{8}

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  cos x - sin x = √2 cos (3 x)

Dividing '√2' on both sides , we get

\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }

we will use trigonometry formulas

a) Cos ( A + B) = Cos A Cos B - sin A sin B

b)  cos \frac{\pi }{4} = \frac{1}{\sqrt{2} }

<u><em>Step(ii):-</em></u>

<u><em></em></u>\frac{1}{\sqrt{2} } cos (x) - \frac{1}{\sqrt{2} } sin (x) = \frac{\sqrt{2} cos (3 x)}{\sqrt{2} }<u><em></em></u>

cos (\frac{\pi }{4} ) cos x - sin(\frac{\pi }{4} ) sin x = cos 3x

cos (\frac{\pi }{4}+x ) = cos 3 x

<u><em>Step(iii):-</em></u>

<u><em>General solution of  cos x = cos ∝  is  x = 2 nπ+∝</em></u>

<u><em>we have </em></u> cos (\frac{\pi }{4}+x ) = cos 3 x

The general solution of  cos (\frac{\pi }{4}+x ) = cos 3 x is

⇒  3 x   = 2 n \pi  + (\frac{\pi }{4}+x )

⇒ 3 x- x = 2 n \pi + \frac{\pi }{4}

 2x = 2 n \pi + \frac{\pi }{4}

<em><u>final answer</u></em>:-

General solution is

 x = n \pi + \frac{\pi }{8}

             

8 0
3 years ago
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