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In-s [12.5K]
3 years ago
7

A gas at constant temperature is confined to a cylinder with a movable piston. The piston is slowly pushed into the cylinder, de

creasing the volume of a gas. The pressure increases. What are the variables in this experiment? (What is changing?)
a. temperature and time
b. time and volume
c. volume and pressure
d. pressure and temperature
Physics
2 answers:
Inessa [10]3 years ago
4 0
C. Volume and pressure
Key words: increases and decreases
Romashka [77]3 years ago
4 0
The answer is C. Volume and pressure
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A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral frag
statuscvo [17]
P=M÷V
p=28.7÷5.74
p=5

The density is 5.
8 0
3 years ago
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f your risk-aversion coefficient is A = 4 and you believe that the entire 1926–2015 period is representative of future expected
siniylev [52]

Answer:

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

Explanation:

As the complete question is not given here ,the table of data is missing which is as attached herewith.

From the maximized equation of the utility function it is evident that

Weight=\frac{E_M-r_f}{A\sigma_M^2}

For the equity, here as

  • Weight is percentage of the equity which is to be calculated
  • {E_M-r_f} is the Risk premium whose value as seen from the attached data for the period 1926-2015 is 8.30%
  • A is the risk aversion factor which is given as 4.
  • \sigma_M is the standard deviation of the portfolio which from the data for the period 1926-2015 is 20.59

By substituting values.

Weight=\frac{E_M-r_f}{A\sigma_M^2}\\Weight=\frac{8.30\%}{4(20.59\%)^2}\\Weight=0.4894 =48.94\%

So the weight of equity is 48.94%.

Now the weight of T bills is given as

Weight_{T-Bills}=1-Weight_{equity}\\Weight_{T-Bills}=1-0.4894\\Weight_{T-Bills}=0.5105=51.05\%\\

So  the weight of T-bills is 51.05%.

The portfolio should invest 48.94% in equity while 51.05% in the T-bills.

7 0
3 years ago
A certain parallel-plate capacitor is filled with a dielectric for which Κ = 5.5 .The area of each plate is 0.034 m2 , and the p
Nesterboy [21]

Answer:

The maximum energy that can be stored in the capacitor is  6.62 x 10⁻⁵ J

Explanation:

Given that,

dielectric constant k = 5.5

the area of each plate, A = 0.034 m²

separating distance, d =  2.0 mm = 2 x 10⁻³ m

magnitude of the electric field =  200 kN/C

Capacitance of the capacitor is calculated as follows;

C = \frac{k \epsilon A}{d} = \frac{5.5*8.85*10^{-12}*0.034}{2*10^{-3}} = 8.275 *10^{-10} \ F

Maximum potential difference:

V = E x d

V = 200000 x 2 x 10⁻³ = 400 V

Maximum energy that can be stored in the capacitor:

E = ¹/₂CV²

E = ¹/₂ x 8.275 x 10⁻¹⁰ x (400)²

E = 6.62 x 10⁻⁵ J

Therefore, the maximum energy that can be stored in the capacitor is  6.62 x 10⁻⁵ J

4 0
3 years ago
As a capacitor is being charged in an RC circuit. the current flowing through a resistor isa) increasingb) decreasingc) constant
Montano1993 [528]
<h2>Answer: decreasing</h2>

An RC circuit is an electrical circuit composed of resistors and capacitors, where the charging time T of the circuit is proportional to the magnitude of the electrical resistance R and the capacity C of the capacitor.  

As shown below:

T=R.C

In this context, the electrical resistance is the opposition to the flow of electrons when moving through a conductor.

Therefore:

<h2>When a capacitor is being charged in an RC circuit, the current flowing through a resistor <u>decreases</u>.</h2>

And the correct option is b.

4 0
3 years ago
Problem #1- In the first scene in which Miss Clark appears, she is supposed to be wearing a BLACK dress.
katrin [286]

Answer:

Blue Lighting

Explanation:

In order to make red look black, you must use blue light. The blue would be absorbed and there would be no red light to reflect.

6 0
3 years ago
Read 2 more answers
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