1. Using Strong Permanent. 2. increasing the current. 3. Decreasing the space between Magnets
Explanation:
Brainiest
Explanation:
Below is an attachment containing the solution.
v1 = 6m/s
v2 = 0
∆v = v1 - v2 = 6m\s
s = t * v = 15m
t = s\v1 = 15(m) \ 6(m\s) = 2.5s
a = ∆v\t = 6(m\s) \ 2.5s = 2.4m\s2
a = F\m = 2.4m\s2
F = a * m = 2.4m\s2 * ?kg
I can't tell you this because I don't know the mass of this cyclist
The historical method includes what steps?
This problem here is an example of inelastic collision where kinetic energy is not conserved but momentum is. We calculate as follows:
m1v1 + m2v2 = (m1 + m2)v3
v3 = m1v1 + m2v2 / m1 + m2
v3 = (30.2)(1000) + (5000)(0) / (30.2 + 5000)
v3 = 6.00 m/s
