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In-s [12.5K]
3 years ago
7

A gas at constant temperature is confined to a cylinder with a movable piston. The piston is slowly pushed into the cylinder, de

creasing the volume of a gas. The pressure increases. What are the variables in this experiment? (What is changing?)
a. temperature and time
b. time and volume
c. volume and pressure
d. pressure and temperature
Physics
2 answers:
Inessa [10]3 years ago
4 0
C. Volume and pressure
Key words: increases and decreases
Romashka [77]3 years ago
4 0
The answer is C. Volume and pressure
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A car accelerates from rest at -3.00m/s^2. What is the velocity at the end of 5.0s? What is the displacement after5.0s?
Andrew [12]

Speed = (acceleration) x (time)
Velocity = (speed) in (direction of the speed)

Speed = (-3 m/s²) x (5 s) = 15 m/s
Velocity =
             (15 m/s) in the direction opposite to the direction you call positive
.

Displacement = (distance between start-point and end-point)
                           in the direction from start-point to end-point.

Distance = (1/2) (acceleration) (time)²
Distance = (1/2) (3 m/s²) (5 s)²
                 = (1/2) (3 m/s²) (25 s²)  =  37.5 meters

Displacement =
                     37.5 meters in the direction opposite to the direction you call positive.

5 0
3 years ago
Name 3 different types of graphs that can be used to plot data.
siniylev [52]

Answer:

Bar graph

Pie graph

Line Graph

Explanation:

mark as brainliest and drop some thanks!!!

7 0
3 years ago
Read 2 more answers
Figure 1 shows the motion of three balls. The curved paths followed by balls B and Care examples of
nlexa [21]

Answer:

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7 0
3 years ago
Calculate the acceleration using the formula acceleration = (final velocity - initial velocity) / time.
PtichkaEL [24]

Answer:

10 km/hr/s

Explanation:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time

For the car in this problem:

u = 0

v=60 km/h

t = 6 s

Substituting in the equation,

a=\frac{60 km/h-0}{6s}=10 km/h/s

6 0
3 years ago
Suppose a ball is dropped from shoulder height, falls, makes a perfectly elastic collision with the floor, and rebounds to shoul
Bezzdna [24]

Answer:Same magnitude

Explanation:

When ball is dropped from shoulder height h then velocity at the bottom is given by

v_1=\sqrt{2gh}

if it makes elastic collision then it will acquire the same velocity and riser up to the same height

If m is the mass of ball then impulse imparted is given by

J=m(v_2-v_1)

J=2m\sqrt{2gh}

Thus impulse imparted by gravity and Floor will have same magnitude of impulse but direction will be opposite to each other.

7 0
3 years ago
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