The mass of hydrazine (N₂H₄) required to produce 96 g of water (H₂O) is 85.4 g (Option C)
<h3>Balanced equation </h3>
N₂H₄ + O₂ —> N₂ + 2H₂O
Molar mass of N₂H₄ = (2×14) + (4×1) = 32 g/mol
Mass of N₂H₄ from the balanced equation = 1 × 32 = 32 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H₂O from the balanced equation = 2 × 18 = 36 g
SUMMARY
From the balanced equation above,
36 g of H₂O were produced by 32 g of N₂H₄
<h3>How to determine the mass of N₂H₄</h3>
From the balanced equation above,
36 g of H₂O were produced by 32 g of N₂H₄
Therefore,
96 g of H₂O will be produced by = (96 × 32) / 36 = 85.4 g of N₂H₄
Thus, 85.4 g of N₂H₄ is needed for the reaction
Learn more about stoichiometry:
brainly.com/question/14735801
H₂SO₃ is weaker acid than H₂SO₄.
The bonding power of an acid is typically influenced by the size of the "SO₄" atom; the smaller the "SO₄" atom, the stronger the H-A bond. The atoms get larger and the bonds get weaker as you proceed down a row in the Periodic Table, strengthening the acids.
<h3>Describe acid.</h3>
The term "acid" refers to any molecule or ion that can donate a proton (a Brnsted-Lowry acid) or establish a covalent bond with an electron pair (a Lewis acid). The first class of acids is the proton donors, also known as Brnsted-Lowry acids.
Its chemical name is lysergic acid diethylamide, or LSD as it is more often known. Because it has a potent hallucinogenic impact, using it could alter how you see the world and its objects. The effects of LSD are referred to as tripping.
The term "acid" is frequently used to denote aqueous solutions of acids with a pH lower than 8, even though the technical meaning of the term only pertains to the solute.
To learn more about acid visit:
brainly.com/question/14072179
#SPJ4
Answer : Option A) Translation
Explanation : A composition of reflections over parallel lines is the same as a <u>Translation.</u>
To identify if the composition of reflections over parallel lines are same as translation or not?
We can check using a picture of some shape in the plane. Place the picture on the right side of two vertical parallel. Now, we can see the reflected the shape over the nearest parallel line, then check the reflection over the other parallel line. We see that the shape winds up in the same orientation, like it was just shifted over to the right. Hence, it is translation.
<span>The answer to question 2 is C. A magnifying glass is an example of a plano-convex lens, where one side of the lens is flat and the other is a convex curve. The answer to question 3 is either B or C. A converging lens is curved on both sides and so the rays of light coming out of it converge at a point, which is known as the focal point. When the object is inside the focal point, the image is real and inverted. If it is inside the focal point, the image is virtual and upright. Therefore the image in this question will be upright. The focal length is the distance between the image that is being magnified and the centre of the magnifying lens. A real image can only be formed when the object is further away from the lens than the focal length. Therefore, in this question, the image is virtual, as the object is closer to the lens than the focal length. The answer to question 4 is D because the index of refraction cannot be less than 1. The answer to question 5 is D because only concave mirrors can produce real images; other types produce virtual images. For question 6, the answer is D. In the rainbow, each of the colours refracts at a slightly different angle; red has the smallest refractive index and violet the largest. Of the options, orange is closest to red. For question 12, A is the answer. A higher operating temperature is not a reason fluorescent lamps are better than incandescent lamps because they have a lower operating temperature. Question 15: all of these are characteristics of different electromagetic waves. For question 18, B is true - special care must be taken when low illuminance is required to reduce glare. The answer to question 19 is B - a compound microscope makes use of two lenses. For question 20, the answer is 5 meters away. The illuminance (E) is equal to light intensity (I) divided by the square distance from the light source (d). Therefore, 4 = 100/d squared. To switch this around, d squared is equal to 100/4 = 25. Then find the square root of 25, which is 5.</span>