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maksim [4K]
3 years ago
12

26)

Chemistry
1 answer:
inessss [21]3 years ago
3 0

Answer:

LiO2

Explanation:

One Lithium per 2 Oxygen

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Mention two functions performed by the concentrated sulfuric acid in the reaction ​
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Concentrated sulfuric acid is used as a catalyst, and has a dual role:

-Speeds up the reaction.

-Acts as a dehydrating agent, forcing the equilibrium to the right and resulting in a greater yield of ester.

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How many hydrogen atoms are in water, H2O?<br><br> A) 1<br> B) 2<br> C) 3<br> D) 0
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21+ Cl2 → 12+201 -
Alina [70]

Answer:

\rm 2\; I^{-} + Cl_2 \to I_2 + 2 \; Cl^{-}.

Start color: yellowish-green.

End color: dark purple.

Assumption: no other ion in the solution is colored.

Explanation:

In this reaction, chlorine gas \rm Cl_2 oxidizes iodine ions \rm I^{-} to elemental iodide \rm I_2. At the same time, the chlorine atoms are converted to chloride ions \rm Cl^{-}.

Fluorine, chlorine, bromine, and iodine are all halogens. They are all found in the 17th column of the periodic table from the left. One similarity is that their anions are not colored. However, their elemental forms are typically colored. Besides, moving down the halogen column, the color becomes darker for each element.

Among the reactants of this reaction, \rm I^{-} is colorless. If there's no other colored ion, only the yellowish-green hue of \rm Cl_2 would be visible. Hence the initial color of the reaction would be the yellowish-green color of \rm Cl_2.

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5 0
3 years ago
When aqueous solutions of K3PO4 and Ba(NO3)2 are combined, Ba3(PO4)2 precipitates. Calculate the mass, in grams, of the Ba3(PO4)
Firdavs [7]

Answer:

Mass of Ba₃(PO₄)₂ = 0.0361 g

Explanation:

Given data:

Volume of Ba(NO₃)₂ = 1.2 mL (1.2 × 10⁻³ L )

Molarity of Ba(NO₃)₂ = 0.152 M

Volume of K₃PO₄ = 4.2 mL (4.2 × 10⁻³ L)

Molarity of K₃PO₄ =  0.604 M

Mass of Ba₃(PO₄)₂ produced = ?

Solution:

Chemical equation:

3Ba(NO₃)₂  + 2K₃PO₄  → Ba₃(PO₄)₂  + 6KNO₃

Number of moles of Ba(NO₃)₂ = Molarity × Volume in litter

Number of moles of Ba(NO₃)₂ = 0.152 M × 1.2 × 10⁻³ L

Number of moles of Ba(NO₃)₂ = 0.182 × 10⁻³ mol

Number of moles of K₃PO₄ = Molarity × Volume in litter

Number of moles of K₃PO₄ = 0.604 M × 4.2 × 10⁻³ L

Number of moles of K₃PO₄ = 2.537 × 10⁻³ mol

Now we will compare the moles of Ba₃(PO₄)₂ with K₃PO₄ and Ba(NO₃)₂ .

              Ba(NO₃)₂        :         Ba₃(PO₄)₂

                   3                :               1

              0.182 × 10⁻³    :              1/3 ×0.182 × 10⁻³ = 0.060 × 10⁻³ mol

                K₃PO₄           :          Ba₃(PO₄)₂

                   2                 :                1

              2.537 × 10⁻³     :               1/2 ×  2.537 × 10⁻³= 1.269 × 10⁻³ mol

The number of moles of Ba₃(PO₄)₂ produced by  Ba(NO₃)₂  are less it will limiting reactant.

Mass of Ba₃(PO₄)₂ = moles × molar mass

Mass of Ba₃(PO₄)₂ = 0.060 × 10⁻³ mol × 601.93 g/mol

Mass of Ba₃(PO₄)₂ = 36.12 × 10⁻³ g

Mass of Ba₃(PO₄)₂ = 0.0361 g

6 0
3 years ago
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