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juin [17]
3 years ago
15

the science building is 5.25 m tall a. How many decimeters is it? b. How many millimeter is it? *show work*​

Physics
2 answers:
Anastasy [175]3 years ago
5 0

Answer:

5.25m to 52.5 Decimeters (10x)

5.25m to 5250 Millimeters (1000x)

12345 [234]3 years ago
4 0
If I remember correctly m means meter (hopefully) so it’s 52.5 decimeters.
And that would mean it would be 5250 millimeters. For the show your work thing, all you really had to do to solve this is move the decimal point depending on what type of measurement you were changing it into. So try and kinda write something like that down where you move the decimal point. Hope this helps
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Two fish swimming in a river have the following equations of motion:
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Answer:

The second fish, X2, is moving faster than the first fish, X1

Explanation:

The given parameters for the equation of motion of the fishes are;

X1 = -6.4 m + (-1.2 m/s)×t

X2 = 1.3 m + (-2.7 m/s)×t

The given equation are straight line equations in the slope and intercept form, where the slope is the speed and in m/s and the intercept is the starting point of swimming of the fishes

For the first fish, the intercept = -6.4 m, the slope = the  speed = -1.2 m/s

For the second fish, the intercept = 1.3 m, the slope = the  speed = -2.7 m/s

Whereby the fishes are swimming in the opposite direction of the measurement of length, we have;

The magnitude of the speed of the second fish \left | -2.7 \ m/s \right | = 2.7 \ m/s, is larger than the magnitude of the speed of the first fish \left | -1.2 \ m/s \right | = 1.2 \ m/s

Therefore, the second fish, X2, is moving faster than the first fish, X1.

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3 years ago
If each Coulomb of charge is given 20 Joules of energy, what is the voltage of the battery?
Assoli18 [71]

Answer:

Explanation:

V = J/C

V = 20/1

= 20 v

Option A is the correct answer

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A wire of a given material has an electric field of 0.100 mV/m when a potential is applied. The wire has 8.49 x 1028 conduction
Bond [772]

The uniform current density in the wire is 5.43 x 10²⁷ A/m².

<h3>Current density in the wire</h3>

The uniform current density in the wire is calculated as follows;

J = total current / total area

The given parameters:

  • Conduction of the wire = 8.49 x 10²⁸ e/m²
  • time, t = 2.5 x 10⁻¹⁴ s

J = \frac{I}{A} = \frac{Q}{At} \\\\J = \frac{8.49 \times 10^{28}e/m^3 \ \times \ 1.6 \times 10^{-19} \ C/e}{2.5 \times 10^{-14} \ s \ \times ( 0.1 \times 10^{-3} \ V/m)} \\\\J = 5.43 \times 10^{27} \ A/m^2

Learn more about current density here: brainly.com/question/15266434

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