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guapka [62]
3 years ago
9

Can someone please help me please?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer (Please vote me Brainliest if this helps!):

The solution is B.

Step-by-step explanation:

Solve with the quadratic formula

x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\cdot \:1\cdot \:13}}{2\cdot \:1}

Simplify

x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{3}i}{2\cdot \:1}

Separate the solutions

x_1=\frac{-\left(-7\right)+\sqrt{3}i}{2\cdot \:1},\:x_2=\frac{-\left(-7\right)-\sqrt{3}i}{2\cdot \:1}

\frac{-\left(-7\right)+\sqrt{3}i}{2\cdot \:1}

Apply rule - (-a) = a

\frac{7+\sqrt{3}i}{2\cdot \:1}

Multiply the numbers: 2 · 1 = 2

\frac{7+\sqrt{3}i}{2}

\frac{-\left(-7\right)-\sqrt{3}i}{2\cdot \:1}

Apply rule - (-a) = a

\frac{7-\sqrt{3}i}{2\cdot \:1}

Multiply the numbers: 2 · 1 = 2

\frac{7-\sqrt{3}i}{2}

The solutions to the quadratic equations are:

\frac{7+\sqrt{3}i}{2}, \frac{7-\sqrt{3}i}{2}

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